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Angle 100° is quarter times greater than its supplementary angle 80°.
Solution:
let 'x' be the required angle and 'y' be its complementary angle.
x+y=180°
Now, x is quarter times greater than y.
That is, x=y+¼y.
therefore x=y+0.25y
=1.25y
thus, 1.25y + y = 180°
2.25y = 180°
y=80°
thus, x=1.25 X 80
=100°
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Which one is greater a meter or a inch?
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Which has a greater momentum a small pick up truck traveling at 55km an hour or a full-sized bus traveling at the same speed?
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If the measure of an angle is 4 times its supplementary angle what are the angles?
An angle and the angle that it is supplementary to have a total measure of 180 degrees.Let x be the supplementary angle. 4x would be the original angle.x + 4x = 1805x = 180x = 364x = 144So the two angles are 144 degrees and 36 degrees.
The supplement of an angle measures 10 times its complement What is the measure of the angle?
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). But, 180 - A = 10(90 - A) = 900 - 10A 9A = 720 A = 80° The supplementary angle = 100° and the complementary angle = 10°
What is the measure of angle T when T is 35 degrees greater than 4 times the measure of its supplement?
Supplementary angles add up to 180°. T - 35 = 4(180 - T) = 720 - 4T 5T = 720 + 35 = 755 T = 151° and its supplementary angle is therefore 29°.
The measurement of one angle is 8 times the measurement of the other if they are supplementary what do the two angle mesure to?
20o & 160o
If the degree measure of an angle is 40 and deg less than 3 times the degree measure of its supplementary angle what is the degree measure of the angle?
Let the angle be ( x = 40^\circ ). The supplementary angle is ( 180^\circ - x = 140^\circ ). According to the problem, ( x ) is 40 degrees less than three times its supplementary angle, which can be expressed as ( x = 3(140) - 40 ). Solving this gives ( x = 420 - 40 = 380 ), which contradicts ( x = 40 ). Therefore, the angle cannot satisfy the given condition.
What is the angle whose supplementary angle is 4 times its complementary angle?
Suppose the angle is x degrees. Then supplementary angle = 180 - x and compementary = 90 - x So, 180 - x = 4*(90 - x) ie 180 - x = 360 - 4x or 3x = 180 or x = 60 degrees.
One of two supplementary angles is 9 times as large as the other How large is the smaller of the two angles?
Supplementary angles are angles which add to 180o. So, one angle is nine times as large as the other, therefore letting the smaller angle be X, we have the following: 9X + X = 180 10X = 180 X=18o and the other is 9 times this amount or 162o
If angle a and B are supplementary angles and angle a is two times as large as angle B find the measures of angle and angle B?
If angles A and B are supplementary, their measures add up to 180 degrees. Let angle B be ( x ). Then angle A, being twice as large, is ( 2x ). Setting up the equation, we have ( x + 2x = 180 ), which simplifies to ( 3x = 180 ). Solving for ( x ), we find ( x = 60 ) degrees for angle B, and angle A measures ( 120 ) degrees. Thus, angle A is 120 degrees and angle B is 60 degrees.
What are measures of two supplementary angles if angle A is 5 less than 4 times the measure of angle B?
from the given information,we get, angle b = x angle a = 4x - 5 we know that supplementary angles have 180 degree as their sum , so, 4x - 5 + x = 180 5x - 5 = 180 5x = 185 x = 37 so,angle a = 4x - 5 = 4 *37 -5 = 143 angle b = 37 also angle a + angle b = 143 + 37 = 180
The measure of one angle is seven more than three times he measure of another angle if the two angles are supplementary find the positive difference of the measures of the two angles?
Angle 'A' is 7 more than 3 times angle 'B': A = 3B + 7 The angles are supplementary: A + B = 180 or A = (180 - B) (180 - B) = 3B + 7 180 = 4B + 7 173 = 4B B = 43.25 degrees A = 136.75 degrees Their difference is 93 degrees.
Two angles are supplementary.The second angle has a mesaure five times that of the first Find the measure of the angle?
Suppose the angle is x then the second is 5x. The two angles are supplementary so x + 5x = 180 or 6x = 180 so that x = 30 degrees.
What is the measure of an angle whose measure is 5 times that of its compliment?
Two complementary angles add up to 90 degrees. Hence, the problem can be set up and solved. Let x represent one angle and 5x represent the angle that is 5 times greater: x + 5x = 90 (simplify) 6x = 90 (next divide both sides by 6 to find the value of x [the smaller angle]) x = 15 (this is the smaller angle, next subtract 15 from 90 to find the greater angle) 90 - 15 = 75 (this is the greater angle which is 5 times that of its complement)
