The volume of an irregular object can most accurately be determined by its displacement in water.
Fill a container to the brim, and stand it in a tub of some description. When you submerge the irregular object, the quantity of water displaced (ie. overflowing into the tub) will be equal to the volume of the object.
The accuracy of this method will be determined by your ability to measure the quantity of water and the purity of it (pure H20 being ideal).
This was first discovered by Archimedes, who used the displacement of water to ensure the kings crown was solid gold.
By multiplying the object's length, width, and height.
The volume of the object.
By using Archimedes principle which is by immersing the object in water and noting its displacement by its apparent loss of weight when suspended on a balance
To find the volume of an irregular object such as a rock, you have to use displacement. If you place the object in a graduated cylinder filled with water, the volume of the object is equal to the amount of water that the object displaces. For example, if a graduated cylinder is filled with 100mL of water, and you place an object such as a rock and the water rises from 100mL to 106mL, then the volume of the rock is 6.
If you submerge the object in a volumetrically-labeled beaker, the volume of water displaced (how much the water rises when the object is submerged), is the volume of the object.Either a graduated cylinder or overflow can is used to measure the volume of an irregular solid by water displacement.
The density of a non-uniform object can be found by using its mass and volume. The volume can be measured by placing the object in volumetric glassware filled with water. The increase in volume is equal to the volume of the object. The object can then be weighed using a scale. The density of the object will be given by the ratio of mass / volume.
By placing the object in water and the volume of water displaced is equal to the volume of the object immersed
by a graduated cylinder (don't rely on this answer i am not sure of it)
For an irregular shaped object that cannot be measured and then volume calculated with a formula.
by applying archemedes priciples, volume of the water displaced is equal to the voulume of the irregular object , measured by using a mesuring jar
Irregular solid volume is still measured in cm3 etcTo Find the Volume of an irregular object you can,Measure out a proportional amount of water to the object you are finding the volume ofPut the object in the container of waterSee how much the water has risen byYou now have the volume!!(The difference between the new and old volumes of water is the volume
The easiest way to do it if the object is not water soluble, is to carefully fill a graduated beaker with water and note the volume carefully. Place the object to be measured in the water making sure that it is completely submerged. Read the new water level in the beaker. subtract the new volume from the starting volume. The difference is the volume of the irregular object.
The water displacement method is typically used to find the volume of an irregular solid. The object is submerged in a known amount of water, and the increase in water volume is measured. This increase in volume is equal to the volume of the irregular solid.
you put the shape into sections and find there volumes and add your answers together
To calculate the volume of an irregular object you will need a container with meaurements and water. Place the irregular object in your container and fill with water until the entire object is covered. Record volume A. Then remove the irregular object and record volume B. The volume of your irregulare object is equal to volume A minus volume B.
Volume of irregular or regular shape object is the space reserved by the object in any medium.
Partition (or divide) the irregular object into summation of regular objects and then calculate the volume.
Volume of irregular or regular shape object is the space reserved by the object in any medium.