Photons, the basic element of light do not have a charge.
First of all, bulbs are not normally rated in volts, they are usually recognised by how much energy they use per second (measured in Watts). However, in context of the question, there are two basic properties of an electrical circuit; current and voltage. Current is defined as the rate of flow of charge. That means that if a current of 1 amp flows for 1 second, 1 coulomb of charge is transferred. The equation is: Q=IT Charge transferred (in Coulombs) = Current (in Amps) x Time (in Seconds) Voltage is defined as the energy per unit charge: V=W/Q Voltage (in Voltage) = Energy transferred (in Joules) / Charge transferred (in Coulombs) Theoretically, based on these two equations, if you reduce the voltage but keep the current the same, the energy transferred is halved and thus, the light given out by the bulb will be halved. However, depending on what bulb it may not light at all as an LED (light emitting-diode) will only light if there is a bigger voltage than its threshold voltage. Its threshold voltage is the point where as voltage increases beyond that point, the LED's resitance would be almost zero and the bulb will light. A Filament lamp is a non-ohmic conductor (as is an LED) because the resistance is not constant as the voltage increases. This is because as the voltage increases, the energy it transfers is more and the lamp heats up. This heat vibrates the metal lattice of the wire and inhibits electron flow (charge carriers) through the metal and so its resistance increases. Thus depending on the bulb and its resistance, it may light or it may not. A simple answer to all this is, the bulb may light or not depending on the bulb and current across it. This is assuming that the length and cross-sectional area of the wire as well as the number of electron charge carriers (electron number density of the material) is constant.
An incandescent light uses electric current passing through a wire with a high resistance to current flow. That makes the wire very hot and it glows, producing the light. A fluorescent light uses electricity to charge a gas in a tube. The charged gas glows, producing the light. For the same amount of light, more electricity is needed in an incandescent light than in a fluorescent light, but developing and building fluorescent lights required more advanced technology than did incandescent lights.
On their own metals have no charge. Metal ions have a positive charge.
A neutron doesn't have an electrical charge; its electric charge is zero.
Partial charge are charge that are smaller than the charge of the electron.And, they are produced by distribution of electrons in chemical bonds.
No. Light does not carry a charge.
Alfred Lord Tennyson was the author of the poem 'The Charge of the Light Brigade'.
Charge of the Light Brigade, 1854. During the battle of battle-of-balaclava(25 October 1854)
negative charge
The charge of the Light Brigade
1854 = charge of the light brigade - are you dumb?
The Charge of the Light Brigade - 1898 was released on: USA: January 1898
1756
Maybe the LED has gone, maybe a fuse has blown. Does your DS charge? does it power on? is it JUST the charge light that doesn't come on? Need a bit more info :)
"The Charge of the Light Brigade" was a poem written in response to the Charge of the Light Brigade (a British cavalry unit) to their death at the Battle of Balaclava on October 25th, 1854 during the Crimean War.
it has a positive charge so the negative item attract to it if it is light enough
It has to do with your battery charge. it's either charging or is at full charge.