Since we need to shift 5 decimal places to the right to obtain the value in scientific notation, n = -5 for base 10.
4
0.00032 in scientific notation is 3.2*10-4
3572069 in Scientific Notation = 3.572069 x 10^6
New discoveries affect our lives in that; we have more stuff that helps us do our daily activities faster and more efficiently. New discoveries also affect employment because they use machines to replace human employment.
Example sentence - I had to replace the batteries in the flashlight in order for it to work.
You could replace it with a 3A fuse. You should never replace a fuse with one which is rated higher.
It depends on what m is and where it appears!
In scientific notation it is: 7.0*105
0.00032 in scientific notation is 3.2*10-4
3572069 in Scientific Notation = 3.572069 x 10^6
There are 7 numbers (zeros) after the 9. So, the n is 7.
No you cannot the answer is False
False. You can only replace it with a number from the domain of the function.
Dim average as doubleDim numberA as integer = 23Dim numberB as integer =2Dim numberC as integer = 27 'continue until you have enough numbersaverage = numberA + numberB + numberC '...average = average / 3 ' replace 3 with the amount of numbers used.
it is false!
yes,because it could be right or wrong while when the theory became a law it will not be replace anymore.
The following is for F95 and later (due to the use of intrinsic SUM ): My assumptions: -Your numbers are integers -Your numbers are stored in an array -The numbers you are describing are 0-100 program findSum !I assumed integer, replace this with your data type integer, dimension(100) :: numbers integer :: sumOfNumbers !We populate an array with our numbers !Replace this with your numbers do i=1,(size(numbers)+1) numbers = i end do !We find the sum of those numbers sumOfNumbers = sum(numbers) !We write out the sum to prompt write(*,*) 'Sum is: ', sumOfNumbers end program findSum
There are no other official or scientific words that are used to replace the word gold. Coins are often a symbol of gold though.