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What does 2x45-7 equal?
2x45-7 is equal to 83.
What numbers are multiplied to make 90?
1x90, 2x45, 3x30, 5x18, 6x15, 9x10 2x3x15, 2x5x9, 3x5x6
What are the factors of 40 and 90?
Factors of 40 : 1X40 , 2X20 , 4X10 , 5X8 Factors of 90 : 1X90 , 2X45 , 3X30 , 5X18 Common factors : 1,2,5
What times what is 90?
1x90 2x45 3x30 5x18 6x15 9x10 All of these work, and the opposites work as well. If both numbers are made negative, that works as well. There are an infinite number of fractional answers, so I will refrain from listing those
What time what equals 90?
There are infinitely many possible answers: 2*45 or 0.03*3000 assuming that you want whole number factors 1x90, 2x45, 3x30, 5x18, 5x15, 9x10 and, if you want integers use the same pairs with both numbers negative
What times 2 equals 90?
4545 * 2 = 90You can do this in your mind by adding 40 + 40 = 80, then add the two fives 5 + 5 = 10, and add those two sums together. 80 + 10 = 90.
What is divisible 90 by?
90 is divisible by 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, and 90. Because 1x90=90 2x45=90 3x30=90 5x18=90 and so on, try starting to divide by the lowest numbers and work your way up.
What is the gcf of 90 480?
The easiest way to find the GCF (in my opinion) is to find out what numbers mulitply to 90 and 480:90: 1x90; 2x45; 3x30; 5x18; 6x15; 9x10(You know you can stop at 9x10 because after 10, at 6x15, is 15. The numbers go in order if you list it out: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90)You can do the same thing for 480.480: 1x480; 2x240; 3x160; 4x120; 5x96; 6x80; 8x60; 10x48; 12x40; 15x32; 16x30You can stop at 16x30 because when you compare it with the factors with 90, you can see that 480 does not have any factors with 90 and 45, so the next highest is 30.Answer: 30
How many feet will take to stop at 60 mph?
That depends on the deceleration applied, in which casetime = 2x45 mph/a = 90/awith a (the deceleration) measured in miles per hour per hour to give the time in hours.If you mean the time that would be taken using the stopping distances in the UK Highway Code, then, assuming a constant deceleration (from the moment the brakes are applied after the thinking distance):The stopping distance at 45 mph is 45 ft (thinking distance) + 101.25 ft (braking distance)[braking distance is speed2 / 20 ft = 452 / 20 ft = 101.25 ft]The thinking distance is travelled at 45 mph, giving:think_time = 45 ft / 45 mph= 45 ft /(45 x 5280 ft / 3600 seconds)= 45 x 3600 / (45 x 5280) seconds= 3600/5280 seconds= 15/22 seconds(This time is constant for all the emergency stopping distances given in the Highway Code.) Two equations of motion can be used to find the stopping time knowing the initial speed and distance (the final speed is zero):final_velocity2 = initial_velocity2 + 2 x acceleration x distancefinal_velocity = 0→ acceleration = - initial_velocity2 / (2 x distance)distance = initial_velocity x time + 1/2 x acceleration x time2→ distance = initial_velocity x time - (1/4 x initial_velocity2 / distance) x time2→ time2 - (4 x distance / initial_velocity) x time + 4 x distance2 / initial_velocity2 = 0→ (time - 2 x distance/initial_velocity)2 = 0→ breaking_time = 2 x distance / initial_velocity= 2 x (101.25 ft) / (45 x 5280 / 3600 ft per sec)= 202.5 x 3600 / (45 x 5280) seconds= 9x15/2x22→ total_stopping_time = 15/22 + 9x15/2x22 seconds= 11x15/2x22 seconds= 15/4 seconds= 33/4 seconds= 3.75 seconds.
