Ba3As2 is barium arsenide. Ba2As3-- doesn'exist.
Barium sulphate
Test for the anions,according to your word,i think you got the salts,so, use these reagents HCL,BACL2,Adding bacl2 and Hcl to Naso4-white ppt observed in soluble,but barium chloride will give no ppt...so probem solved
H2SO4 (aq) + BaCl2 (s) -> BaSO4 (s) + 2HCl (aq)RtL---.I've been typing this up to do as a question for my A-level chemistry. A white precipitate is formed which is barium sulphate (BaSO4) along with (what I believe theoretically) HCl, hydrogen chloride; which when created into a solution in water becomes hydrochloric acid, and an extra hydrogen atom left over.BaCl + H2SO4 ---------> BaSO4 + HCl + HBut the single hydrogen atom can't exist as a gas by itself, and is considered 'unstaable' by itself due to its single unfilled orbital, therefore it wants to bond to other atoms and molecules. As the equation is balanced, the hydrogen will bond with another hydrogen formed from another reaction and be released as hydrogen gas.I hope this answers your question!Jess :)Hi jess,I think u are wrong. Barium chloride exists as BaCl2Hence the reaction isBaCl2 + H2SO4 --> BaSO4 + 2HClSO4 has a -2 charge so Ba will become Ba2SO4.(actually Ba has a +2 charge so it would stay BaSO4)