What does an acceleration of 9.8 meters per second squared mean?

Answer 1

An acceleration of 9.8 meters per second squared means that the velocity of an object is increasing by 9.8 meters per second every second. This value is equivalent to the acceleration due to gravity on Earth, which causes objects to fall towards the ground at a rate of 9.8 m/s^2. In other words, if an object is in free fall near the surface of the Earth, its speed will increase by 9.8 m/s for every second it falls.

Answer 2

Oh, dude, an acceleration of 9.8 meters per second squared means that an object's speed is increasing by 9.8 meters per second every second. It's like when you're driving, and you keep hitting the gas pedal a little harder every second. So, if you're falling due to gravity, you'd be picking up speed at that rate until you hit the ground.

Answer 3

An acceleration of 9.8 meters per second squared means that the velocity of an object is increasing by 9.8 meters per second for each second that passes. This acceleration is equivalent to the acceleration due to gravity on Earth, causing objects to fall at this rate in a vacuum.

Answer 4

That's the acceleration of gravity. For every second a body is falling in Earth-gravity, its speed increases by 9.8 meters per second ever second. Or (9.8 m/s)/s. Since you are basically dividing by seconds twice, it's the same thing as dividing by seconds squared.

Answer 5

Given no force to negate the velocity, an acceleration of 9.8m/s2 means that an object dropped will gain a velocity of 9.8m/s every second - at 0 time with 0 velocity, 1 second later the object is at 9.8 m/s, at 2 seconds the object is moving at 19.6 m/s, 3 seconds 29.4 m/s, 4 seconds 39.2 m/s and so on. Because of wind resistance in the Earth's atmosphere, terminal velocity (final velocity) in the air, falling from the sky from a plane several miles up, is about 120 mph. But note: it's not the fall that kills you, it's the stop. Going from 120 mph to 0 mph in less than a second = smooooshed.

Answer 6

Firstly units are technically m(s^-2)... Or m(/s^2)

Its the second derivative in respect in time of distance.

9.8 is simply due to the gravitational laws: From Newton's law of gravity:

F = K*m1*m2/R^2 From Newton's second law:

F = m2*g K*m1*m2/R^2 = m2*g You get g = K*m1/R^2 Where: * K is the gravitational constant, i.e. 6.67*10^-11 m^3kg^-1s^-2

* m1 is Earth's mass, i.e. 5.97E24 Kg, * and R is the Earth's radius, i.e. 6378 Km If you put these inside the formula, you get 9.8 m/sec^2. If you have more mass, you have higher gravitational field. The value considered in most problems is 9.81 but it does vary SLIGHTLY depending where you are on the earth due to slight differences in mass at different latitudes.

Answer 7

This acceleration is the gravitational constant of Earth. That's how fast an object accelerates in its gravitational field (at "nominal" distances).

From a literal perspective, it means that the velocity of the object is changing by 9.8 meters per second every second. In other words, if an object is motionless at t0, it will be moving at 9.8 meters per second after one second; after two seconds, it will be moving at 19.6 meters per second, and so on.

Answer 8

9.88 meters per second per second - The rate of acceleration of an Object falling within the Atmosphere of a Planet (earth) - determines the strength of the Gravity Force on that Planet under Constant Uniform Motion, which is conventionally held to be: 1G on the Earth.

Thus, "Inertia" is a "mathematical construct" that allows the "Thermodynamic Mechanism," INPUT-PROCESS-OUTPUT, to operate scientifically, in a manner amenable to a process having - a beginning, a duration, and an end, in accordance with the fundamental principle inherent in the Law of Transformation of Energy.

For example, how do we calculate the distance a car is traveling from point A to point B. Well, we assume "a beginning point" at Time t zero. At time T zero, a car leaves point A to travel to point B at a certain "rate of acceleration," which, when held constant, becomes, its "average velocity;" and the car arrives at T1.

But, the car is "moving" even at T zero, due to Constant Uniform Motion, which, in accordance with Relativity Theory, appears to be "at rest" - For, in the Universe, things are always moving; "inertial rest" is relative to "Constant Uniform Motion - e.g., If a train is travelling at a constant velocity of 65 miles per hour- with no abrupt changes in acceleration - two persons can easily "play ping pong" on a tennis table without ever experiencing any disruption, stoppage, deceleration, or shock.

Thus, to determine the "strength of the Gravity Force" on Jupiter, for example, hold the Earth gravity force, 1G, as the "standard" for comparison, and then, analyze the "rate of acceleration of an object falling within the Atmosphere of the Planet Jupiter," and thereby, determine its "gravity force strength" relative to 1G. The rate of acceleration on Jupiter would be expected to be "faster" than "9.88 meters per second per second" due to "greater bulk of Planetary Mass-in-Motion" being propelled per rate of Revolution and Rotation of Jupiter around the Sun and on its own axis, respectively.

Why? Gravity force is present only due to "Mass-in-Motion" as derived from an object being propelled by the force of Electromagnetism, which is the primary force in the whole Universe. For example: Planets revolve around Stars due to the Stars' excessive electromagnetic field within which the Planet's own weaker magnetic field strength is "trapped." The Earth also has a magnetic field consistent with its revolving "hot iron molten magma core," composite interface of which, corresponds to its own "relative interactions" with the Sun's electromagnetic field, thus, causing clockwise Revolution around the Sun, which is then "countered" by anti-clockwise Rotation of the Planet due to Newton's Third Law of Motion - triggering a co-linear, co-equal but OPPOSITE reaction upon the Earth as moved by the relative strength of the Star's electromagnetic field Force.

Thus, due to Constant Uniform Motion, the relative constancy of the velocity rate of Motion, and the quantify of Mass in the Universe, the Speed of Light in a vacuum is relatively fixed at: 186,000 miles per second. In the same vein, the rate of acceleration in Earth Gravity, 1G, is a constant fixed at: 9.88 meters per second squared.

What is an Equation - Very simple! "Left side equals right side." Thus, we are always looking for "relative equivalencies" between two categories of things by studying the relationship between the respective Variables, that are either in "direct proportional relationship" or "inverse relationship." For example: Energy is "excited Matter;" and matter is "congealed Energy," corresponding to the Equation E = mc squared, (direct proportional relationship), which, in consequence, allows us to derive equations: m = E / c squared; and c squared = E / m (in "inverse proportional relationship" or "inverse square law."

Hence, Equations for both Electric Force and the Gravitational Force present "inverse square law" proportional relationships, thus, there is "relative EQUIVALENCY" between the Gravity and Electromagnetism.

Fg = G m1 x m2 / r squared (Force of Gravity)

Force of Gravity = G (gravitational constant in Newtons) multiplied by mass of Object 1 x mass of Object 2 / squared of the distance between them

F(e) = k q0 x q1 / r squared (Electric Force)

Likewise:

Electric Force = Plank's Constant multiplied by "charge 1" x "charge 2" / squared distance between the two charges

Thus, a direct proportional equivalency exists between the Electromagnetism and Gravity. Meaning that, the Force exerted by the Magnetic Field of a Star, e.g., our Sun, to constantly and continually, keep, nine Planets in its revolutionary ellipsoid ecliptic Plane, is "equivalent in value" or " is of the same value as" the Gravity Force, that is derived, from the Motion of the bulk of the Planets' Masses, respectively, as they are being "propelled" by the Star's Electromagnetic Force, to move in their specific rates of Revolution and Rotation upon their own axes. ***

Answer 9

Yes, acceleration due to gravity (typically represented by the letter "g") is 9.8 m / s2. With 2 decimal places, g = 9.81 m / s2.

Answer 10

The acceleration 9.8 m/s^2 is equivalent to acceleration due to gravity on Earth.