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That's the acceleration of gravity. For every second a body is falling in Earth-gravity, its speed increases by 9.8 meters per second ever second. Or (9.8 m/s)/s. Since you are basically dividing by seconds twice, it's the same thing as dividing by seconds squared.

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16y ago
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15y ago

Given no force to negate the velocity, an acceleration of 9.8m/s2 means that an object dropped will gain a velocity of 9.8m/s every second - at 0 time with 0 velocity, 1 second later the object is at 9.8 m/s, at 2 seconds the object is moving at 19.6 m/s, 3 seconds 29.4 m/s, 4 seconds 39.2 m/s and so on. Because of wind resistance in the Earth's atmosphere, terminal velocity (final velocity) in the air, falling from the sky from a plane several miles up, is about 120 mph. But note: it's not the fall that kills you, it's the stop. Going from 120 mph to 0 mph in less than a second = smooooshed.

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14y ago

Firstly units are technically m(s^-2)... Or m(/s^2)

Its the second derivative in respect in time of distance.

9.8 is simply due to the gravitational laws: From Newton's law of gravity:

F = K*m1*m2/R^2 From Newton's second law:

F = m2*g K*m1*m2/R^2 = m2*g You get g = K*m1/R^2 Where: * K is the gravitational constant, i.e. 6.67*10^-11 m^3kg^-1s^-2

* m1 is Earth's mass, i.e. 5.97E24 Kg, * and R is the Earth's radius, i.e. 6378 Km If you put these inside the formula, you get 9.8 m/sec^2. If you have more mass, you have higher gravitational field. The value considered in most problems is 9.81 but it does vary SLIGHTLY depending where you are on the earth due to slight differences in mass at different latitudes.

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14y ago

This acceleration is the gravitational constant of Earth. That's how fast an object accelerates in its gravitational field (at "nominal" distances).

From a literal perspective, it means that the velocity of the object is changing by 9.8 meters per second every second. In other words, if an object is motionless at t0, it will be moving at 9.8 meters per second after one second; after two seconds, it will be moving at 19.6 meters per second, and so on.

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2y ago

9.88 meters per second per second - The rate of acceleration of an Object falling within the Atmosphere of a Planet (earth) - determines the strength of the Gravity Force on that Planet under Constant Uniform Motion, which is conventionally held to be: 1G on the Earth.

Thus, "Inertia" is a "mathematical construct" that allows the "Thermodynamic Mechanism," INPUT-PROCESS-OUTPUT, to operate scientifically, in a manner amenable to a process having - a beginning, a duration, and an end, in accordance with the fundamental principle inherent in the Law of Transformation of Energy.

For example, how do we calculate the distance a car is traveling from point A to point B. Well, we assume "a beginning point" at Time t zero. At time T zero, a car leaves point A to travel to point B at a certain "rate of acceleration," which, when held constant, becomes, its "average velocity;" and the car arrives at T1.

But, the car is "moving" even at T zero, due to Constant Uniform Motion, which, in accordance with Relativity Theory, appears to be "at rest" - For, in the Universe, things are always moving; "inertial rest" is relative to "Constant Uniform Motion - e.g., If a train is travelling at a constant velocity of 65 miles per hour- with no abrupt changes in acceleration - two persons can easily "play ping pong" on a tennis table without ever experiencing any disruption, stoppage, deceleration, or shock.

Thus, to determine the "strength of the Gravity Force" on Jupiter, for example, hold the Earth gravity force, 1G, as the "standard" for comparison, and then, analyze the "rate of acceleration of an object falling within the Atmosphere of the Planet Jupiter," and thereby, determine its "gravity force strength" relative to 1G. The rate of acceleration on Jupiter would be expected to be "faster" than "9.88 meters per second per second" due to "greater bulk of Planetary Mass-in-Motion" being propelled per rate of Revolution and Rotation of Jupiter around the Sun and on its own axis, respectively.

Why? Gravity force is present only due to "Mass-in-Motion" as derived from an object being propelled by the force of Electromagnetism, which is the primary force in the whole Universe. For example: Planets revolve around Stars due to the Stars' excessive electromagnetic field within which the Planet's own weaker magnetic field strength is "trapped." The Earth also has a magnetic field consistent with its revolving "hot iron molten magma core," composite interface of which, corresponds to its own "relative interactions" with the Sun's electromagnetic field, thus, causing clockwise Revolution around the Sun, which is then "countered" by anti-clockwise Rotation of the Planet due to Newton's Third Law of Motion - triggering a co-linear, co-equal but OPPOSITE reaction upon the Earth as moved by the relative strength of the Star's electromagnetic field Force.

Thus, due to Constant Uniform Motion, the relative constancy of the velocity rate of Motion, and the quantify of Mass in the Universe, the Speed of Light in a vacuum is relatively fixed at: 186,000 miles per second. In the same vein, the rate of acceleration in Earth Gravity, 1G, is a constant fixed at: 9.88 meters per second squared.

What is an Equation - Very simple! "Left side equals right side." Thus, we are always looking for "relative equivalencies" between two categories of things by studying the relationship between the respective Variables, that are either in "direct proportional relationship" or "inverse relationship." For example: Energy is "excited Matter;" and matter is "congealed Energy," corresponding to the Equation E = mc squared, (direct proportional relationship), which, in consequence, allows us to derive equations: m = E / c squared; and c squared = E / m (in "inverse proportional relationship" or "inverse square law."

Hence, Equations for both Electric Force and the Gravitational Force present "inverse square law" proportional relationships, thus, there is "relative EQUIVALENCY" between the Gravity and Electromagnetism.

Fg = G m1 x m2 / r squared (Force of Gravity)

Force of Gravity = G (gravitational constant in Newtons) multiplied by mass of Object 1 x mass of Object 2 / squared of the distance between them

F(e) = k q0 x q1 / r squared (Electric Force)

Likewise:

Electric Force = Plank's Constant multiplied by "charge 1" x "charge 2" / squared distance between the two charges

Thus, a direct proportional equivalency exists between the Electromagnetism and Gravity. Meaning that, the Force exerted by the Magnetic Field of a Star, e.g., our Sun, to constantly and continually, keep, nine Planets in its revolutionary ellipsoid ecliptic Plane, is "equivalent in value" or " is of the same value as" the Gravity Force, that is derived, from the Motion of the bulk of the Planets' Masses, respectively, as they are being "propelled" by the Star's Electromagnetic Force, to move in their specific rates of Revolution and Rotation upon their own axes. ***

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14y ago

Yes, acceleration due to gravity (typically represented by the letter "g") is 9.8 m / s2. With 2 decimal places, g = 9.81 m / s2.

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14y ago

The acceleration 9.8 m/s^2 is equivalent to acceleration due to gravity on Earth.

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12y ago

Poor estimate of gravitational velocity or force on earth.

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15y ago

Earth's gravity @ sea level

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14y ago

yes

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Q: What does an acceleration of 9.8 meters per second squared mean?
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What does it mean to have second squared in the denominator of the unit for acceleration due to gravity?

Intriguing, right? - The basic idea is that acceleration is a change in velocity over time; and velocity is expressed in meters per second. So if, for example, an object changes its velocity from zero to 5 m/s, within one second, you will have an acceleration of (5 m/s) per second, or 5 m/s/s, or simply. 5 m/s2. The "second squared" by itself has no physical significance, only as part of larger units, such as acceleration, force (equals mass x acceleration), work (equals force times distance), etc.


What does 9.8 meters per second squared mean?

It means that if you start at 0m/s, after 1 second you go 9.8m/s, the next second, your speed is 19.6m/s, the third second your speed is 27.4 m/s, and you get faster and faster. This is a standard unit of acceleration, and particularly a standard figure for gravity (9.81m/s2)


Which would fall with greater acceleration in a vacuum a leaf or a stone?

Assuming by 'fall' we mean undergo the effects of gravity. If the two objects are falling toward the same large mass (ie falling towards Earth) then they would both accelerate at the same rate. This rate happens to be about 9.8 meters per second squared. It is the acceleration due to gravity on earth.


What is the only factor needed to calculate change in velocity due to acceleration of gravity?

What is the only factor needed to calculate change in velocity due to acceleration of gravity 9.8 ms?


The acceleration of gravity is a constant equal to what meters per second squared?

the acceleration due to grvity in m/s^2 on eath is 9.8m/s^2

Related questions

What is the mean of 2g?

g is a measurement of acceleration namely 9.8 meters per second squared. When there is an acceleration of 2g then simply multiply 9.8 meters per second squared times 2 or 19.6 meters per second squared.


Does Mercury have a strong or weak gravity?

If you mean the acceleration due to gravity on the surface, that's about 3.7 meters per second squared; for comparison, gravity on Earth is 9.8 meters per second squared.


What does meters per second squared mean?

ms^-2 or m/s^2 is a unit used to measure acceleration.


What does and acceleration of five meters per second squared mean about the velocity of the object?

It means that the object's speed is always 5 meters per second faster than it was one second earlier.


What is earths gravitational acceleration rate?

The mean acceleration rate due to gravity on the Earth is 9.81 meters per second squared ( 9.81 m/s^2 ) or 32.17 feet per second squared ( 32.17 ft/s^2 ).


How much force is needed to accelerate an 1800 kg truck 4 meters per second?

Force = mass * acceleration and acceleration is in units of meters per second squared. I will assume you mean this. m/s2 Force = (1800 kg)(4 m/s2) = 7200 Newtons ----------------------


What is the numerial value in meters per second squared of acceleration of an object experience true free fall?

I presume you mean acceleration due to gravity on earth (ignoring any air resistance). It is approx. 9.81 ms-2.


How much does its speed change after 5 minutes with an acceleration of 470 meters per second?

"470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed.


What is the number of the gravity?

I am not quite sure what you mean. The Moon's surface gravity is about a sixth of the Earth's surface gravity. That means the acceleration due to gravity on the Moon is about 1.62 meters per second squared.


What does it mean to have second squared in the denominator of the unit for acceleration due to gravity?

Intriguing, right? - The basic idea is that acceleration is a change in velocity over time; and velocity is expressed in meters per second. So if, for example, an object changes its velocity from zero to 5 m/s, within one second, you will have an acceleration of (5 m/s) per second, or 5 m/s/s, or simply. 5 m/s2. The "second squared" by itself has no physical significance, only as part of larger units, such as acceleration, force (equals mass x acceleration), work (equals force times distance), etc.


Could the rate of acceleration of an object be seen as meters per second per second per second?

Didn't mean to type here...


Is acceleration in the ISU?

If you mean the SI (international system of units), the derived unit for acceleration is meters per square second. There is no special name for this unit.