The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The distance and displacement are the same when the displacement is parallel to itself or straight. Displacement is a vector and distance is a real number or scalar. If an object is displaced around a circle the displacement is zero and the distance is 2pi r.
6.5 m at 67 degrees north of east
1 mile East
The answer is 80 because 100-30+10 is 80.
Type your answer here... C.3.5 km at 50º north of west
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The total displacement is 2km north, as the southward and northward displacements cancel each other out.
The resultant is 2 km South.
2 km south
north, 35 degrees north of east
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
To find the correct displacement, we need to consider the net movement in the north-south direction. Starting from the origin, you move 4 km south, then 2 km north, resulting in a net movement of 2 km south. Next, moving 5 km south brings the total to 7 km south, and finally moving 5 km north results in a net position of 2 km south. Thus, the correct displacement is 2 km south.
4-2+5-5 = 2 km south. It's simple addition, keeping track of the plus and minus signs (south is plus, north is minus).
find the resultant of the following displacement a=20km 30south of east
The displacement of the hiker can be found by treating the eastward and northward movements as vectors. Using the Pythagorean theorem, the displacement is the square root of the sum of the squares of the distances traveled in each direction. In this case, the displacement is √(3.0 km)^2 + (4.0 km)^2 = √(9 km^2 + 16 km^2) = √25 km^2 = 5.0 km. Therefore, the displacement of the hiker is 5.0 km in a direction that is 53.1 degrees north of east.