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How is distance and displacement the same?
The distance and displacement are the same when the displacement is parallel to itself or straight. Displacement is a vector and distance is a real number or scalar. If an object is displaced around a circle the displacement is zero and the distance is 2pi r.
A duck waddles 2.5 m east and 6.0 m north what are the magnitude and direction of the duck's displacement with respect to its original position?
6.5 m at 67 degrees north of east
What is the displacement of a cyclist who travels 1 mile north then1 mile east and finally 1 mile south what is it?
1 mile East
Mike walks 100 meters north then walks 30 meters south. After this he walks another 10 meters north. What is the magnitude of his total displacement during this walk in meters?
The answer is 80 because 100-30+10 is 80.
A truck travels to and from a stone quarry that is located 2.5 km to the east what is its displacement?
Type your answer here... C.3.5 km at 50º north of west
What is the correct displacement for the following vectors 4 km south km north 5 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south .5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4km south 2km north 5km south and 5km north?
The total displacement is 2km north, as the southward and northward displacements cancel each other out.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south and 5 km north?
The resultant is 2 km South.
What are displacement vectors of 2 km south and 6 km north and 5 km south and 6 km north combine to a total displacement of?
2 km south
What are not vectors?
north, 35 degrees north of east
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
What is the correct displacement for the following 4km south 2km north5km south5km north?
To find the correct displacement, we need to consider the net movement in the north-south direction. Starting from the origin, you move 4 km south, then 2 km north, resulting in a net movement of 2 km south. Next, moving 5 km south brings the total to 7 km south, and finally moving 5 km north results in a net position of 2 km south. Thus, the correct displacement is 2 km south.
What is the correct desplacment of the following vectors 4km south 2km north 5km south 5 km north?
4-2+5-5 = 2 km south. It's simple addition, keeping track of the plus and minus signs (south is plus, north is minus).
How do you find north south east west?
find the resultant of the following displacement a=20km 30south of east
What is the displacement of a hiker who travels 3.0 km east and then 4.0 km north?
The displacement of the hiker can be found by treating the eastward and northward movements as vectors. Using the Pythagorean theorem, the displacement is the square root of the sum of the squares of the distances traveled in each direction. In this case, the displacement is √(3.0 km)^2 + (4.0 km)^2 = √(9 km^2 + 16 km^2) = √25 km^2 = 5.0 km. Therefore, the displacement of the hiker is 5.0 km in a direction that is 53.1 degrees north of east.
