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They're the same. They're the same.
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∙ 15y ago
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What is the difference between a manipulated and responding variable?
Manipulated variables are also known as independent variables. These are the variable which you change in an investigation. Plotted on the x axis.
What is the difference between sterilization and commercial sterilization?
The difference is that commercial sterilization takes place in irradiation chambers and regular sterilization does not. A irradiation chamber can hold up to 50 tons and is sealed up before the high energy x-rays kills off anything living.
What is a triangular symbol mean in physics?
Usually means the difference, called "Delta".Using /\ for triangle:/\ x means difference in xor is sometimes used to mean a small amount, eg x + /\ means x plus a very small (infinitesimal) amount
How close is 400 meters to 500 yards?
1 yard = 3 feet 1 foot = 0.3048 meter 500 yards = 500 x 3 x 0.3048 meters = 500 x 0.9148 meters =457.4000 meters Difference between 400 meters and 500 yards = 57.4 meters 400 meters is less than 500 yards by 57.4 meters
What is delta in science?
Greek letters such as delta are often used in different contexts. One use that is often given to delta is to indicate the difference between two values. Thus, delta-x can be the same as x2 - x1, where "x2" and "x1" are the values of "x" at different points in time, for example.
What is the integral of arcsinxdx?
The integral of arcsin(x) dx is x arcsin(x) + (1-x2)1/2 + C.
How do you solve cot parenthesis inverse of sin 4 over 7 closed parenthesis?
The inverse sin function I write as arcsin x. Make use of the trignometric relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - (sinθ)2)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - (sin(arcsin(x))2)/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(4/7)) = √(1 - (4/7)2)/(4/7) = √(49/72 - 16/72) ÷ 4/7 = √(49 - 16) x 1/7 x 7/4 = 1/4 x √33
How do you solve cot parenthesis sin to the negative 1 parenthesis 2 over 3 closed parenthesis and another closed parenthesis?
I presume that sin-1x is being used to represent the inverse sin function (I prefer arcsin x to avoid possible confusion). Make use of the trignometirc relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - sin2θ)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - sin2(arcsin(x))/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(2/3)) = √(1 - (2/3)2)/(2/3) = √(9/32 - 4/32) ÷ 2/3 = √(9 - 4) x 1/3 x 3/2 = 1/2 x √5
Does the notation of arcsin x represent the inverse function to sine?
NO FALSE
Arcsin x equals sin-1?
yes y=sinx is x=arcsiny
What is cot parenthesis sin to the negativde 1 parenthesis 2 over 3 closed parenthesis and another closed parenthesis?
If I read that correctly, you have: cot(sin-1(2/3)) which I understand to mean cot(arcsin(2/3)) which has the value 1/2 x √5 sin(arcsin(x)) = x cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ ÷ sinθ ⇒ cot(arcsin(2/3)) = cos(arcsin(2/3)) ÷ sin(arcsin(2/3) = √(1 - sin2(arcsin(2/3))) ÷ sin(arcsin(2/3) = √(1 - (2/3)2) ÷ (2/3) = 1/3 x √(9 - 4) x 3/2 = 1/2 x √5 As the reciprocal trignometric functions have separate names, eg 1/tan x = cot x, the use of the -1 "power" to indicate the inverse function is possible. However, to avoid any possible confusion, I prefer to use the arc- prefix to indicate the inverse function.
How do you solve 2 sin squared x minus sinx minus 1 is equal to 0?
2 sin(x)2 - sin(x) - 1 = 0 Let Y=sin(x) then the equation is 2*Y2 - Y - 1 =0 Delta = (-1 * -1) - 4 * 2 * -1 = 9 Y = (1 + sqrt(9)) / 4 or Y = (1 - sqrt(9)) / 4 Y = 1 or Y = -1/2 Then x = Arcsin(Y) and (in radians) x = Arcsin(1) = Pi/2 +2*k*Pi or x=Arcsin(-1/2) = -Pi/6 + 2*k*Pi where k is an integer
What is x if the sin of x equals square root of 5 divided by 2?
2.5
What is the integral of 1 divided by the square root of the quantity 1 minus the square of x with respect to x?
0
How do you answer the equation integral of x 1 over square root of 1-x2 dx?
This is solved by using substitution: Let x = sin θ → dx = cos θ dθ and √(1 - x²) = √(1 - sin² θ) = cos θ and θ = arcsin x → ∫ (x + 1)/√(1 - x²) dx = ∫ ((sin θ + 1)/ cos θ) cos θ dθ = ∫ sin θ + 1 dθ = -cos θ + θ + b = θ - cos θ + b = arcsin x - √(1 - x²) + c
How do you determine the radius or degrees of an arc knowing only the length and rise?
If the length is L, the rise is R and the angle is x degrees, then sin(x) = R/L so that x = arcsin(R/L) or sin-1(R/L)
What is the integral of f prime divided by the square root of the quantity a squared minus f squared with respect to x where f is a function of x and a is a constant?
∫ f'(x)/√(a2 - f(x)2) dx = arcsin(f(x)/a) + C C is the constant of integration.
