Nitric acid and hydrobromic acid are both "strong acids", so you can treat them as dissociated completely, especially at such a low concentration.
Let's do some calculations and find out what the pH is.
998 grams of HBr (80.91 g/mol) is 12.3 moles.
45 grams of HNO3 (63.01 g/mol) is 0.71 moles.
So total that's 13.0 moles of acid. Divided by 150000 L, that's 8.7x10-5 molar, so the pH will be the negative log of that, or about 4.
The lead carbonate is dissolved in nitric acid and carbon dioxide is released.
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In the parting method, the ore is dissolved in a bath of hot concentrated sulfuric or nitric acid. Gold is recovered from the residue, and the clear solution is treated with ferrous sulfate to precipitate the silver.
The answer depends on what other metals are in the alloy.
Nitrogen dioxide (NO2) reacts with OH in the atmosphere to form nitric acid (HNO3). Nitric acid can also form when nitrogen dioxide (NO2) reacts with the nitrate radical (NO3) in the presence of atmospheric water
strong acids are the acids that ionize completely in an aqueous solution.. egs are sulphuric acid, perchloric acid, hydroiodic acid, fluoroantimonic acid, fluorosulphuric acid, hydrobromic acid, nitric acid..
HBr and HNO3 are both acids. HBr is hydrobromic acid, while HNO3 is nitric acid. They both release hydrogen ions (H+) in aqueous solution, making them acidic.
Yes, nitric acid is present in aqueous solution.
A dilute solution of nitric acid has a lower concentration of nitric acid molecules compared to a concentrated solution. This leads to the dilute solution having a lower acidic strength and being less corrosive. Concentrated nitric acid, on the other hand, has a higher concentration of nitric acid molecules, making it more acidic and corrosive.
Hydrobromic acid reacts with NaOH to form water and sodium bromide. The balanced chemical equation is: HBr + NaOH → H2O + NaBr. Nitric acid reacts with potassium hydroxide to form water and potassium nitrate. The balanced chemical equation is: HNO3 + KOH → H2O + KNO3.
The molarity of nitric acid, HNO3, can vary depending on the concentration of the solution. For example, a 1 M solution of nitric acid would contain 1 mole of HNO3 per liter of solution. It is important to know the concentration or volume of the solution to determine the molarity of nitric acid.
Mercury (as a metal) is soluble in concentrated nitric acid.
Mercury (as a metal) is soluble in concentrated nitric acid.
Millon's reagent is a solution of mercury nitrate in nitric acid. It usually consists of 10 g of mercury nitrate dissolved in 100 mL of nitric acid, resulting in a red-colored reagent that is used to test for the presence of aromatic compounds containing a phenolic hydroxy group.
In a nitric acid solution, you would find nitrate ions (NO3-) and hydrogen ions (H+). Nitric acid (HNO3) ionizes in water to form nitrate ions and hydrogen ions.
To calculate the molarity of nitric acid, you need to determine the number of moles of barium hydroxide used in the neutralization reaction. From there, you can use the balanced chemical equation to find the moles of nitric acid present in the solution. Finally, divide the moles of nitric acid by the volume of the solution in liters to find the molarity.
To separate a solution of hydrochloric and nitric acid, you can use distillation. Since nitric acid is more volatile than hydrochloric acid, heating the solution will allow the nitric acid to vaporize and separate from the hydrochloric acid, which can then be collected as a distillate.