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Well, first we see Arithmetic transmuted into Algebra.

Algebra gives the Relation - accompanied by the inseparable Units: f (Frequency in cycles per second) = c (the Speed of Light at 297,000 km/s) divided by lambda (in meters per cycle) - Problem:

f = 600,000 hertz or cycles per second;

c = 297,000 kilometers per second; and

the Lambda wavelength in meters per cycle - peak to peak - is:

Lambda = 297,000,000 meters per second divided by 600,000 cycles per second is 2,970/6 meters per Wave.

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12y ago
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8y ago

6 meters.

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Q: What is the wavelength of a 6 meters waves?
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