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As a good 'rule of thumb', you should use 4/3 , meaning that the speed of light in water
is 75% of its speed in vacuum.
There are at least three reasons that we're being cagey and somewhat evasive:
1). Water is a dispersive medium ... the speed of light through it is slightly different for
different colors, which means the index of refraction depends on the light's wavelength.
2). It also depends on the temperature of the water.
3). You'd think that the refractive index of water would be something that's been
very precisely measured and is very accurately known. But it's not. Different methods
of measurement yield slightly different results, and there are slightly different numbers
in the published literature.
So, as we said, for the level of accuracy required by people who go to WikiAnswers
for their experimental parameters . . . . . use 4/3 .
What else can I help you with?
What does light do when it enters a medium?
refraction occurs if the medium is water. or it bounces of a solid,my guess :D
How could the index of refraction of salt water be used to find the concentration of salt solution?
Maybe this isn't the answer you're looking for, but the index of refraction of saline solutions of various concentrations is well known. You would just use a table...
If a glass prism were in a medium with the same index of refraction would it separate wight light into different color?
No, it would not.
What is the relevance of the large value of refractive index of diamond in costume jewelry?
The high index of refraction of diamond produces a rainbow effect of multi-colored glitter. This is difficult to reproduce in the less expensive materials used for costume jewelry.
Describe an experiment to find the refractive index of a glass block?
You can investigate fraction in glass using a rectangular glass block. By tracing the rays of light on a piece of paper, you can measure the angles of incidence (i) and refraction (r). If you repeat this process for a range of different angles of incidence, you would find that the sine of the angle of incidence and the sine of the angle of refraction are constant. This ratio is called the refractive index of the material, and is given the letter n.The angles of incidence and refraction are related by the following equation:sin in=__________sin r
How do you think increasing a medium's index of refraction might affect the angle of refraction?
Increasing the medium's index of refraction will cause the angle of refraction to decrease. This is because light bends more towards the normal as it enters a medium with a higher index of refraction.
How does the angle of refraction change as the index of refraction of the bottom material increases?
As the index of refraction of the bottom material increases, the angle of refraction will decrease. This relationship is governed by Snell's Law, which states that the angle of refraction is inversely proportional to the index of refraction. Therefore, higher index of refraction causes light to bend less when entering a denser medium.
How does increasing a mediums index of refraction affect the angle of refraction?
Increasing the medium's index of refraction causes the angle of refraction to decrease when light passes from a medium with a lower index of refraction to a medium with a higher index of refraction. This is due to the relationship described by Snell's Law, which governs the change in direction of a light ray as it passes from one medium to another.
What is the index of refraction of air at room temperature?
The index of refraction of air at room temperature is approximately 1.0003.
When light passes from a medium with a high index of refraction into a medium with a lower index of refraction which direction does the light bend?
A medium with a higher index of refraction, like diamond, is more dense than the medium with a lower index of refraction, like air. If the ray of light is moving from the less dense medium (lower index of refraction), to a more dense (higher index of refraction) the ray of light bends TOWARDS the normal.
When the mineral uvarovite has an index of refraction of 1.86. calculate the speed of light in this sample of uvarovite?
Use the definition of "index of refraction". In this case, you simply need to divide the speed of light in a vacuum by the index of refraction.
How can the index of refraction for different substances be determined mathematically?
The index of refraction of a substance can be determined mathematically using Snell's Law, which relates the angle of incidence and refraction to the refractive indices of the two substances involved. By measuring the angles of incidence and refraction, the index of refraction can be calculated using the formula n = sin(i) / sin(r), where n is the refractive index, i is the angle of incidence, and r is the angle of refraction.
How to calculate index refraction?
Index of refraction can be calculated using the formula n = c/v, where n is the index of refraction, c is the speed of light in a vacuum, and v is the speed of light in the medium. Just divide the speed of light in a vacuum by the speed of light in the medium to find the index of refraction for that medium.
What is the formula for the index of refraction?
The formula for calculating the index of refraction is n = c/v, where n is the index of refraction, c is the speed of light in a vacuum, and v is the speed of light in the medium.
What is the index of refraction of CR 39?
The index of refraction of CR-39 lens material is approximately 1.498.
How can the critical angle be calculated using the measured index of refraction?
The critical angle can be calculated using the measured index of refraction by using the formula: critical angle arcsin(1/n), where n is the index of refraction of the material.
Why index of refraction of ruby is less than the index of refraction of diamond?
The index of refraction of a material is related to the speed of light in that material. Ruby has a lower index of refraction than diamond because light travels faster through the ruby compared to diamond. This difference is due to the different arrangement of atoms and the properties of the materials.
