The "gram" is a unit of mass. Different substances pack more or less mass
into the same volume ... the characteristic expressed by their "density".
So the volume of 90g depends on what substance you have 90g of.
-- 90g of air, or any other gas, at low pressure, could fill the Superdome.
-- 90g of water comes up to about 3.2 fluid ounces in a measuring cup.
-- But even that is about 19 times the volume of 90g of gold.
240 grams of what?
If it was water, then 240 milliliters.
If it was Mercury then it would only be one 13.7 th as much.
If it was air then it would take a much bigger space.
90mL would occupy a volume of 90cc (cubic centimeters).
graphing of data
18 cm^3
1g water vapour occupies the greatest volume - even at high pressure. 1g of liquid water occupies the least volume. 1g of solid ice is greater volume than liquid water - and this is the only common liquid where the solid is of less volume than the liquid state.
The answer would be 3 times 3 times 3. First you dont need to know the volume of it because to get the mass you do length times width times height.The answer is 27. Thanx for the question.
First convert the number of grams of CO2 into moles, then use the Ideal Gas Law. For how to solve this problem, see the two Related Questions links to the left of this answer.
Based on the formula Desnity= Mass/Volume. The answer would be 13.5 g/cm3
Yes. The volume is less than 20ml.
6.28cm^3
(32.0 g/46.0 g/mol) (0.0821 atm) (291.0 K) / 3.12 atm
The volume of ammonia is 19,5 L.
The volume is 102 mL.
lead and water will occupy the same volume. however the Density of lead is 207.2 g/L (grams per liter) and the Density of H2O is only 18.02 g/L so if you had the same volume of lead and water the lead would be heavier. But if you had the same Weight of both water and lead the water would have a larger volume.
4 g (1 mole) of helium will occupy 22.414 liters. So, 15 g will occupy 84.05 liters
The volume is 16,85 L.
With the provided quantity of mass and density the volume of liquid would be 1000cm3. density = mass / volume → volume = mass / density = 2500 g / (2.5 g/cm^3) = 1000 cm^3 = 1 litre.
4 g of helium occupy 22.414 liters. So, 84.6 g of helium occupy 474.056 liters.
0.00922 g of H2 gas will occupy approximately 0.100 L at STP
396 g of what? - It really depends on the specific substance. The formula to use is:volume = mass / density
35.2 g * 1 g/ml = 35.2 ml