The "gram" is a unit of mass. Different substances pack more or less mass
into the same volume ... the characteristic expressed by their "density".
So the volume of 90g depends on what substance you have 90g of.
-- 90g of air, or any other gas, at low pressure, could fill the Superdome.
-- 90g of water comes up to about 3.2 fluid ounces in a measuring cup.
-- But even that is about 19 times the volume of 90g of gold.
1g water vapour occupies the greatest volume - even at high pressure. 1g of liquid water occupies the least volume. 1g of solid ice is greater volume than liquid water - and this is the only common liquid where the solid is of less volume than the liquid state.
The answer would be 3 times 3 times 3. First you dont need to know the volume of it because to get the mass you do length times width times height.The answer is 27. Thanx for the question.
Based on the formula Desnity= Mass/Volume. The answer would be 13.5 g/cm3
The volume of gas that 3.5 moles of oxygen occupy can be easily found using the relationship of PV=nRT where P is the pressure, V is the volume, n is the moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
Yes. The volume is less than 20ml.
To find the volume of 15.7 g of calcium chloride with a density of 2.50 g/cm³, you would use the formula: Volume = Mass / Density. Plug in the values: Volume = 15.7 g / 2.50 g/cm³ = 6.28 cm³. Therefore, 15.7 g of calcium chloride would occupy a volume of 6.28 cm³.
6.28cm3
The volume 396g would occupy depends on the density of the substance. To calculate the volume, you need to know the density of the material. By dividing the mass (396g) by the material's density (in g/cm^3 or g/mL), you can determine the volume occupied by 396g of that substance.
The density of calcium chloride is approximately 2.15 g/cm3. By dividing the mass by the density, you can calculate the volume. In this case, 15.7 g of calcium chloride would occupy around 7.3 cm3 of volume.
The volume of ammonia is 19,5 L.
To find the volume of 15.7 g of calcium chloride, you would need to know the density of calcium chloride. Without this information, it's not possible to calculate the volume.
The volume of carbon tetrachloride can be calculated using the formula: Volume = Mass / Density. So, the volume of 35.2 g of carbon tetrachloride with a density of 1.00 g/ml would be 35.2 ml.
With the provided quantity of mass and density the volume of liquid would be 1000cm3. density = mass / volume → volume = mass / density = 2500 g / (2.5 g/cm^3) = 1000 cm^3 = 1 litre.
0.00922 g of H2 gas will occupy approximately 0.100 L at STP
To find the volume of 10.0 grams of cork, you need to know its density, which is approximately 0.24 grams per cubic centimeter (g/cm³). Using the formula for volume (Volume = Mass/Density), the volume would be calculated as follows: Volume = 10.0 g / 0.24 g/cm³, resulting in a volume of about 41.67 cm³. Therefore, 10.0 grams of cork would occupy approximately 41.67 cubic centimeters.
lead and water will occupy the same volume. however the Density of lead is 207.2 g/L (grams per liter) and the Density of H2O is only 18.02 g/L so if you had the same volume of lead and water the lead would be heavier. But if you had the same Weight of both water and lead the water would have a larger volume.
The volume of a substance can be calculated using its density. The density of gold is approximately 19.3 g/cm³. Using the formula: Volume = Mass / Density Volume = 180 g / 19.3 g/cm³ Volume ≈ 9.33 cm³ Therefore, 180.0 g of gold will occupy approximately 9.33 cm³.