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What else can I help you with?
What is it that belongs to you yet is used by others more than you?
your name! lol i have heard this riddle dozens of times b4.
What is a homosaphian?
It is scientific name for humans. Scientists have developed a system to name all the species on this planet. Each animals has a species name and a genus name.
What is a good name for a batch name?
khankirpola
What is LizO name science?
CaNr2 name
What is the scientific name of Jack-fruit scientific name?
Artocarpus heterophyllus is the scientific name of Jackfruit
Who is bx cable name after?
BRONX
What is the name of An equation of the form ax2 bx c 0?
If you mean: ax2+bx+c = 0 then it's the general form of a quadratic equation
What famous person has the initials BX?
The famous person with the initials BX is Billie Eilish, whose full name is Billie Eilish Pirate Baird O'Connell. While her initials technically don't match, she is often referred to by her stage name, which can be creatively abbreviated as "BX" in some contexts. However, there isn't a widely recognized public figure with the initials BX in the entertainment industry.
What does bx stand for in bx cable?
Bronx
Write a program to subtract two 16 bit numbers in microprocessor 8086?
.code main proc mov ax,@data mov ds,ax lea dx,msg ;printing msg mov ah,09h int 21h mov ax,x ;ax=x mov bx,y ;bx=y cmp ax,0 ;jump to l3 if ax is negtive jb l3 cmp bx,0 ;jump to l6 if bx is negative jb l6 cmp ax,bx ;if ax<bx,then jump to l1 jl l1 sub ax,bx ;else normal sub mov diff,ax ;diff=result is stored jmp l2 l1: ;iff (+)ax<(+)bx neg bx ;bx=-bx clc add ax,bx neg ax ;-ans=ans mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l3: ;iff (-)ax neg ax ;-ax=ax cmp bx,0 ;jump to l4 if bx is negative jb l4 clc add ax,bx ;ax=(+)ax+(+)bx mov ax,diff mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l4: ;if (-)ax & (-)bx neg bx ;-bx=bx cmp ax,bx ;if ax>bx then jump to l5 jg l5 sub ax,bx ;else ax-bx mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l3 l5: ;if(-)ax>(-)bx xchg ax,bx ;exchange ax and bx sub ax,bx ;ax-bx mov diff,ax ;ans is positive jmp l2 l6: ;iff (-)bx neg bx ;-bx=bx add ax,bx ;ax-(-)bx mov diff,ax ;ans will be positive mov ah,4ch int 21h main endp
Program to subtract two 8 bit numbers using 8086 microprocessor?
I have a code for 16 bit subtraction.. just replace ax by al,bx by bl etc... .code main proc mov ax,@data mov ds,ax lea dx,msg ;printing msg mov ah,09h int 21h mov ax,x ;ax=x(any number) mov bx,y ;bx=y( " ") cmp ax,0 ;jump to l3 if ax is negtive jb l3 cmp bx,0 ;jump to l6 if bx is negative jb l6 cmp ax,bx ;if ax<bx,then jump to l1 jl l1 sub ax,bx ;else normal sub mov diff,ax ;diff=result is stored jmp l2 l1: ;iff (+)ax<(+)bx neg bx ;bx=-bx clc add ax,bx neg ax ;-ans=ans mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l3: ;iff (-)ax neg ax ;-ax=ax cmp bx,0 ;jump to l4 if bx is negative jb l4 clc add ax,bx ;ax=(+)ax+(+)bx mov ax,diff mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l4: ;if (-)ax & (-)bx neg bx ;-bx=bx cmp ax,bx ;if ax>bx then jump to l5 jg l5 sub ax,bx ;else ax-bx mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l3 l5: ;if(-)ax>(-)bx xchg ax,bx ;exchange ax and bx sub ax,bx ;ax-bx mov diff,ax ;ans is positive jmp l2 l6: ;iff (-)bx neg bx ;-bx=bx add ax,bx ;ax-(-)bx mov diff,ax ;ans will be positive mov ah,4ch int 21h main endp
When was Citroën BX created?
Citroën BX was created in 1982.
When was BX Warrior created?
BX Warrior was created in 2006.
When was Toyota BX created?
Toyota BX was created in 1951.
Was silver ever used in bx wire?
No, silver was never used in BX cable.
How do you write a code to complement the corresponding bit in bx if AX contains 6complement the 6th bit of BX in assembly?
To complement the 6th bit of the BX register in assembly language, you can use the XOR instruction. The 6th bit corresponds to the bit mask 0x20 (binary 0010 0000). The code would look like this: MOV AX, 6 ; Load AX with 6 (not directly relevant to complementing BX) XOR BX, 0x20 ; Complement the 6th bit of BX This will toggle the 6th bit of BX, effectively complementing it.
Solve bx plus cy equals d for x?
bx+cy=d bx=d-cy x=d-cy ----- b answer: d-cy ----- b
