0.1 M
The formula of formaldehyde is CH2O. The products formed are sodium formate (HCOONa) and methanol (CH3OH). The stoichiometric equation is then X CH2O + Y NaOH --> A HCOONa + B CH3OH. Balancing the equation makes the coefficients 2 CH2O + NaOH --> HCOONa + CH3OH.
Methanal, more commonly known as formaldehyde, is an organic compound with the formula CH2O. It was used for years to preserve deceased biological specimens before it was deiscovered to be carcinogenic.
-ol is the suffix used in IUPAC nomenclature to indicate an alcohol group, -OH. The systematic name for alcohols is alkanols. Examples are methanol, CH3OH, ethanol C2H5OH and phenol, C6H5OH. All the numbers should be subscripts.
It is solid calcium chloride. Gases, liquids and solutions have randomly arranged particles.
Alcohols consist of Hydroxyl group, -OH and Alkyl or hydrocarbon chain. for example alcohol C1 : CH3OH methyl alcohol alcohol C2 : C2H5OH ethyl alcohol C3 propyl C4 butyl C5 pen C6 hex ... so on
The concentration of ethanol is 11,7 %.
CH3OH does not ionize because it is insoluble in water
--> number of moles of CH3OH = mass/molar mass 22/(12+3+16+1) = 0.6875 moles --> number of mole = conc multiply by volume(indm3) number of moles divided by volume[indm3] = concentration 0.6875/[.25] = 2.75 mol/dm3
A solution of potassium hydroxide is a better conductor.
The answer is 9.6 grams.
The answer is 3,211 g.
7,207 g methanol are needed.
Methonal does not exist. Methanol (CH3OH) or methanal (CH2O) do exist, which one do you mean.
NaOH + CH3OH --> CH3ONa + H2O Evaporate the solution to dryness, add more CH3OH and evaporate to dryness. you can repeat a few times to ensure the remaining solid is sodium methoxide
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
CH3OH is molecular.
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH