answersLogoWhite

0


Best Answer

0.1 M

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Which concentration of a solution of CH3OH in water has the lowest freezing point?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the concentration (M) of CH3OH in a solution prepared by dissolving 11.7 g of CH3OH in sufficient water to give exactly 100. mL of solution?

The concentration of ethanol is 11,7 %.


What is the total molar concentration of ions in a 1.240 M solution of CH3OH?

CH3OH does not ionize because it is insoluble in water


What is the molar concentration of a solution containing 22.0 g of CH3OH in 250ML?

--> number of moles of CH3OH = mass/molar mass 22/(12+3+16+1) = 0.6875 moles --> number of mole = conc multiply by volume(indm3) number of moles divided by volume[indm3] = concentration 0.6875/[.25] = 2.75 mol/dm3


Which is the better conductor CH3OH or KOH?

A solution of potassium hydroxide is a better conductor.


How many grams of ch3oh must be added to water to prepare 150 ml of a solution that is 2.0 m ch3oh?

The answer is 9.6 grams.


How many grams of CH3OH is needed to make 0.211m solution in 479g of water?

The answer is 3,211 g.


How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 1.5 M CH3OH?

7,207 g methanol are needed.


How much methonal is needed to lower freezing point of fresh water?

Methonal does not exist. Methanol (CH3OH) or methanal (CH2O) do exist, which one do you mean.


How do you get sodium methoxide from sodium hydroxide and methanol?

NaOH + CH3OH --> CH3ONa + H2O Evaporate the solution to dryness, add more CH3OH and evaporate to dryness. you can repeat a few times to ensure the remaining solid is sodium methoxide


What is the mass in grams of 9.32x1024 molecules of methanol CH3OH?

9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH


Is CH3OH ionic or molecular?

CH3OH is molecular.


What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?

9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH