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We can't see the drawing, so we don't know how QX is related to AB. Maybe
that's the whole problem. Perhaps you ought to look at the drawing.
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∙ 12y ago
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Area of a triangle with a 10 foot base and 8 foot height?
The answer is 40. Area of triangle = ba/2 where b = length of the base, a = length of corresponding height. Therefore, 10 X 8/2 = 80/2 = 40.
A 64cm strip is cut into 8 equal pieces write the length of one in mm?
64 divided by 8 is 8. 1 cm = 10 mm. 8 multiplied by 10 is 80. 80 mm.
What is the perimeter of a regular pentagon with a side length of 7.2 cm?
we know that regular pentagon has 5 equilateral triangle . now ,perimeter of pentagon = 5 Xside . now,perimeter of a regular pentagon with a side length of 7.2 cm . perimeter = 7.2 X 5 =36 cm .
How many inches are in a cup?
An inch is a unit of length. A cup is a unit of capacity. The two units are therefore incompatible.
Convert 1.125 into inches?
There is no way to answer this because you have not included any units to compare.
If a (0 0) and b (8 2) what is the length of ab?
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
If A (-2 -4) and B (-8 4) what is the length of line AB?
End points: (-2, -4) and (-8, 4) Length of line AB: 10
If A is the point -2 -4 and B is -8 4 what is the length of AB?
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
If A (-2 -4) and B (-8 4) what is the length of Ab?
Using the distance formula the length of ab is 5 units
If A is the point -2 -4 and B is the point -8 4 what is the length of AB?
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
If A(-2-4) and B(-8-4) what is the length of AB?
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
In triangle pqr qx perpendicular pr and py perpendicular qr. if pq10cm qr8cm and pr5.6cm find the length of py where qx 7.2cm?
There is a problem with your question: If pq = 10 cm, qr = 8 cm and pr = 5.6 cm then if qx is perpendicular to pr through q it does NOT equal 7.2 cm; it is approx 8.0 cm: Let X be the distance px, then xr = 5.6 - X Using Pythagoras: In pxq: 10² = qx² + X² → qx² = 10² - X² In rxq: 8² = qx² + (5.6 - X)² → qx² = 8² - (5.6 - X)² → 10² - X² = 8² - (5.6 - X)² → 10² - X² = 8² - 5.6² + 2×5.6×X - X² → 2×5.6×X = 10² - 8² + 5.6² → X = (10² - 8² + 5.6²)/(2×5.6) → qx² = 10² - ( (10² - 8² + 5.6²)/(2×5.6) )² → qx = √(10² - ( (10² - 8² + 5.6²)/(2×5.6) )²) ≈ 7.989265 cm ≈ 8.0 cm Similarly, for py: py = √(10² - ( (10² - 5.6² + 8²)/(2×8) )²) ≈ 5.59248 cm ≈ 5.6 cm The obtuse triangle has angles: qpr ≈ 53°, prq ≈ 93°, rqp ≈ 34°; the perpendiculars qx and py lie outside the triangle; angle prq ≈ 93° which is not far off a right angle making sides pr and qr approximately perpendicular, and shows that the perpendiculars to the sides next to it (ie the perpendiculars to pr and qr) will be approximately equal to the lengths of the other side (next to it, ie length of perpendicular to pr will be approx qr, and the length of the perpendicular to qr will be approx pr).
If A (-1 -3) and B (11 -8) what is the length of ab?
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Ef is a median of trapezoid abcd if the length of ab is 8x and the length of CD is 20x what is the length of ef in terms of x?
8
If a equals negative 1 -3 and b equals 11 -8 what is the length of AB?
If you mean endpoints of (-1, -3) and (11, -8) then the length works out as 13
If A (10 4) and B (2 19) what is the length of AB?
Length AB is 17 units
If a(-1-3)and b(11-8)what is the length of ab?
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units
