The object and image distance are interchangeable, because this gives rise to points of conjunction, a point on an object has a conjugate point on the image, both will yield the same value for f and it is a property of optical systems known as reversibility.
Use the thin lense equation. 1/f = 1/d + 1/o, where f is the focal length, d is the image distance, and o is the object distance.
distance from mirror
In optics, a virtual image is an image in which the outgoing rays from a point on the object never actually intersect at a visable point. However, if these rays were stretched out they would intersect at a point behind the mirror/surface.
13.7 millimetersThis answer is correct, but the formula is most important.The formula is:Hi = height of imageHo = height of objectSi = Distance of image from lensSo = Distance of object from lensYou are trying to find Si, so that is your unknown.Here is your formula: Hi/Ho = Si/SoOr in this case: 3.5/13 = Si/51The rest is basic algebra.Good luck!You can use the ratio equation; (Image Height)/(object height) = - (image location)/(object location) In your case you will get a negative location which means the image is on the same side of the lens as the incoming light.
The focal point. It can affect size, real/virtual, inverted/upright.
the focal length of the eye lens is adjusted so that the image distance does not change.
when dealing with a flat mirror object-distance and image-distance should be equal.
image distance is the distance from the point of incidence on the mirror, the where the image is reflected to.object distance is the distance from the actual object being reflected to the point of incidence on the mirror where it's reflected as an image.
The distance of the object from the mirror line should equal the distance of the image from the mirror line.
the image distance will appear the same
Sum of reciprocal of object distance and reciprocal of image distance gives the reciprocal of focal length
Sum of reciprocal of object distance and reciprocal of image distance gives the reciprocal of focal length
1.Image distance= object distance 2.Size of the image = size of the object 3.image is laterally inverted 4.Image is always virtual & erect
It's a ratio of Image distance to the Object distance.
2 cm
The distance between the object and mirror is 15 mm. The distance between the image and mirror is 15 mm. Therefore, the distance between the image and object is 15 mm plus 15 mm which equals 30 mm.
The distance of object and the distance of image.