You are standing on top of a 140 foot tall bridge You throw a baseball upward from your shoulder 5 ft above your feet with an initial velocity of 95 footsec What is the maximum height of the baseball?

Answer 1

This problem can be solved simply by using the following equation: Vf^2= Vi^2+2*a*d Vf = 0 at the maximum height Vi = 95 ft/s a = acceleration due to gravity = -32 ft/s^2 Plugging these in gives a maximum height from the beginning of the throw as: d= 141 ft However the ball started from a height of 145 ft so the ball reaches a maximum ht of 286 ft.