24 inches x 24 inches is equal to 4 square feet.
100 of these tiles are required to fit 400 square feet.
56 tiles to cover 224 square feet.
A 24 inch tile covers 4 square feet. Doing the math gives an answer of 175 tiles, plus some for spoilage and trim.
The maths is; 6 inch = 0.5 foot & 24 inch = 2 foot therefore 0.5 (height) x 2 (width) x 75 (Sq ft) = 1/2 × 2 = 75
A 24x24 tile is 4 square feet. You would need 105 of them.
24 ft2
400 x 122 / 24 = 400 x 12 / 2 = 2400 tiles if there is no waste.
6 x 24 inch tile = 144 sq in = 1 sq ft 400/1 = 400 tiles
24 of them.
10A 8 foot by 5 foot area would hold 24 four inch square tiles along the 8 foot side and 15 along the 5 foot side, so the total quantity of would be 360 four inch square tiles (24 x 15).
24 m2 is the same as 240,000 cm2. As each tile is 400 cm2, the number of tiles required to fill the area is 240,000 divided by 400, which equals 600, so you will need 600 tiles.
100
if the tiles are 24 inch by 12 inch, there are 12 inches in one foot so they are 1 foot by 2 feet = 2 square feet each To cover 44 square feet you ned 44/2 = 22 tiles
Without any waste you would need 25 tiles.
875 24-inch tiles.
If this is for an actual tiling job, the answer is 225. First, convert feet into inches. 1 foot = 12 inches. 24 * 12 = 288 inches So your garage is 288 inches by 288 inches. 288 inches / 19.5 inches = 14.77 So you would need 14.77 tiles across and 14.77 tiles deep. Since you are buying whole tiles, you have to round up. So it would be 15 tiles x 15 tiles. 15 * 15 = 225 tiles. Since many of the tiles have to be cut (0.77 of a tile), it is possible to use the other (0.23) as part of the flooring and get away with a few less tiles, but that's not practical in a real tiling job. It would look terrible.
Each tile covers a square foot. So you will need 24 of them, with a couple extra for cutting and spoilage.
A 12x12 inch tile covers one square foot. You will need 24 of them, plus a few for spoilage.