It depends on the definition of a room. What would the minimum width or length measurement be in a space, and still have it considered a room? With a minimum dimension to go off of, must the product of the width and length be exactly 1000 square feet? Must the width and length be in whole numbers?
(1000-2)*180=998*180 You do the calculation.
volume basically is area, so it would be length*height*width. Convert the answer to whatever you want from there, e.g. 1 m3 = 1000 L.
Convert the width, length and height into centimetres. Multiply together and divide the answer by 1000. The measurements need to refer to the interior.
The volume of a box measuring 8 x 10 x 12.5 meters is 8*10*12.5 = 1000 cubic centimeters, since the volume of a box, or rectangular prism, is w * l * h.
6cm=60mm so: 60x30x40=72000cm 1litre=1000cm so 72000/1000=72 cubic cetimetre. 72=capacity
10 possible numbers on each wheel equals 10x10x10 or 1000 combinations possible.
if i got everything right, its 1000
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
1000 units= 1kilounit
The short answer is 1000. This is very easy to visualise: Simply consider each number in the combination to be a digit in a decimal number. We then end up with a three-digit number. Such a three-digit number ranges in value from 000 to 999, or 1000 unique combinations.
1000
Oh, what a happy little question! With 1000 numbers, there are countless combinations you can create. Each number can be combined with any of the other numbers, leading to a vast array of possibilities waiting to be explored. Just like painting a beautiful landscape, the combinations are endless, and you can let your imagination run wild!
1000
Counting from 000 to 999 would give a possible 1000 combinations.
sorry but this isn't possible because they are measurements of opposite standards, yes i am clevr :) It is possible. The formula is 15 x 1000 / 453 = 33.11 / 14 = 2.365 So 15kg is roughtly 2.365 stones!
100 million in Australian numerical measurements 1000 million in UK numerical measurements
If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.