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The length of a rectangle is 1 inch more than 2 times its width the area of the rectangle is 36 square inches what is the length of the rectangle?
9 inches
If area of rectangle is 36 and length is 4 times greater than width what is width?
Area of the rectangle = 36 =Length * Width Assume Width= a Hence Length = 4*a =4a Area = a*4a =36 Therefore, a*a =9 Hence a =3 =Width
If the area of a rectangle is 18 square inches and the length of the rectangle is twice it?
The question is not quite clear in what's it's asking. Presumably it's asking what is the length and width of the rectangle? Let the length be 2x and the width be x: 2x*x = 18 2x2 = 18 Divide both sides by 2: x2 = 9 Square root both sides: x = 3 Therefore: length = 6 inches and width = 3 inches If it is asking what the width is, and the length is twice the area, then the width would be .5 inches. (L= A*2, L=36) (36*.5=18) (L*W=A)
What is the area of a rectangle that is 12cm and 3cm?
36 cm2 Area of a rectangle is length times width, so you would multipy 12cm by 3 cm to get 36 sq. (squared) cm.
The volume of a gift box is 36 cubic inches.The height is 3 inches and the width is 3 inches. What is the length of the box?
Volume 36 cubic inches height 9 inches
What is the area of a rectangle with these measurements Length 54 inches by Width 36 inches?
1944 in. Length x Width = Area
The length of a rectangle is 1 inch more than 2 times its width the area of the rectangle is 36 square inches what is the length of the rectangle?
9 inches
The perimeter of a rectangle is 152 inches The length exceeds the width by 36 inches What is the length and width?
Do-it-in-your-head method:Length + width is half the perimeter, ie 76 inches;76 - 36 = 40;Half of 40 is 20: this is the width;20 + 36 = 56: this is the length.Job done.
If a rectangle has a base and length of 6 inches.Its area is how many square inches?
It would have an area of 36 sq. inches. The formula for finding the area of a rectangle is length times width. 6*6=36.
Find the area of a rectangle with length of 4.7 inches and width of 7.5 inches?
(4.8 x 7.5) = 36 square inches
If the area of a rectangle is 1260 square inches and its length is 36 inches then what is the width?
Rectangle area = L x W1.260 in2 = 36 in x W in (divide both sides by 36 in)35 in = W
If area of rectangle is 36 and length is 4 times greater than width what is width?
Area of the rectangle = 36 =Length * Width Assume Width= a Hence Length = 4*a =4a Area = a*4a =36 Therefore, a*a =9 Hence a =3 =Width
How do you find length of a rectangle if the width is 4 inches and the perimeter is 44?
Perimeter is the distance around the rectangle ... OR (2 X Length) + ( 2 X Width) SO 44 -- (2 X 4) = 36 which is 2 X the Length. 36/2 = 18, which is your answer.
How do you find the width of a rectangle if the area is 36in?
You cannot. First of all, an area cannot be 6 inches since that is a measure of distance, not of an area. So a rectangle with an area of 36 inches is impossible. In any case, assuming the area is 36 SQUARE inches and that the length of the rectangle is at least as great as the width, all that you can say is that the width is at most 6 inches. Suppose the length is L inches where L >= 6 inches. and let W = 36/L inches. Then Area = L*W = L*36/L = 36 sq inches as required. But W is indeterminate.
Perimeter of a rectangle is 140 inches the length exceeds the width by 36 What is the length and the width?
Suppose width = Wthen length L = W + 36 therefore perimeter, P = 2*(L + W) = 2*(W + 36 + W) = 4W + 72 = 140 Therefore 4W = 68 => W = 17 inches and so L = 17 + 36 = 53 inches.
If the area of a rectangle is 18 square inches and the length of the rectangle is twice it?
The question is not quite clear in what's it's asking. Presumably it's asking what is the length and width of the rectangle? Let the length be 2x and the width be x: 2x*x = 18 2x2 = 18 Divide both sides by 2: x2 = 9 Square root both sides: x = 3 Therefore: length = 6 inches and width = 3 inches If it is asking what the width is, and the length is twice the area, then the width would be .5 inches. (L= A*2, L=36) (36*.5=18) (L*W=A)
The area of a rectangle is 36 square inches the length is 1 inch more than twice the width what are the dimensions of the rectangle?
9" x 4"
