perimeter of octagon is 128 cm= 8 * side
side of the octagon=128/8=16 cm
Perimeter = 2*(Length+Width) So 36 = 2*(L+4) 18 = L+4 or L = 14
The third side can be of any length in the interval (2, 128) units of length.
L = 2W 2W x W = 128 2W squared = 128 w squared = 64 W = 8 Width 8 ft, length 16 ft 8 x 16 = 128 QED
16
Let the width be x/2 and the length be x: (x/2)*x = 128 Multiply both sides by 2 and remove the brackets: x2 = 256 Square root both sides: x = 16 Therefore: length = 16 feet and width = 8 feet Check: 16*8 = 128 square feet
16 cm for each side
To find the perimeter of a square, you need to know the length of one side. Since the area of the square is given as 1024, you can find the length of one side by taking the square root of the area. The square root of 1024 is 32, so each side of the square is 32 units long. Therefore, the perimeter of the square is 4 times the length of one side, which is 4 * 32 = 128 units.
128 cm = 50.394 inches.
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
It is: 128/4 = 32 which is a side of the square and so 32*pi is the circumference of the circle
Perimeter = 2*(Length+Width) So 36 = 2*(L+4) 18 = L+4 or L = 14
128
The square root of 128, approxiametaly 11.313
The third side can be of any length in the interval (2, 128) units of length.
128 cm
128 feet.