In terms of footage,a meter is about 39 inches. Multiply 6 by 39 you get 234. Divide 234 by 12 inches in a foot and you get 19.5 feet.
The perimeter would be 28 meters.
L + W = P/2 = 13. 13 - 7 = 6, 6/2 = 3 which is the width, making the length 10.
Area = length x width; 10 m x 6 m = 60 m2 (also written as 60 square metres)
Assuming that the width of the triangle is the base of the triangle and the the length is height we can calculate area as followed: 1/2 Base x Height = Area of a Triangle (8 meters ÷ 2) x 6 meters = 4 meters x 6 meters = 24 meters².
14 meters
If the width is 6 meters, two of the sides are 6 meters each. Therefore the sum of the other two sides is (30 - 2 * 6) meters or 18 meters. So one of the other sides is half of that, 9 meters. Then, of course, the area is the product of the width and the length.
area of a rectangle = length * width. Rearranging, we have width = area / length. Therefore, the width of the rectangle = 31.2 [m2] / 6 [m] = 5.2 [m] ========================
The length of a rectangle whose area is 72 square meters and whose width is 6 meters, would be 12. Note that 12 x 6 = 72.
The perimeter would be 28 meters.
Diagonal = 10 meters.
Prime factors of 55 are 5 and 11, which differ by 6, so length 11m, width 5m!
length = 22 meters and width = 6 meters
12 metres squared. Multiply the length by width
L + W = P/2 = 13. 13 - 7 = 6, 6/2 = 3 which is the width, making the length 10.
6m*5.2m=31.2m
Length = 6* widthArea = 37Area = length * widthArea = 6* width * width37 = 6w^2w = square root of 37/6W = square root(37 / 6) = 2.4832774 meters
Area = length x width; 10 m x 6 m = 60 m2 (also written as 60 square metres)