it is easy
just use de morgan's law
(ab)'=a'+b'
(a+b)'=a'b'
for e.g
pos=(a+b+c)(a'+b+c')
sop=abc+a'bc'
i hope it is clear and easy :)
SOP (sum of products) gives you the answer and POS does not (Unless applying De Morgan's law)
take the whole compliment, since POS is a dual to the SOP form,In the following we apply de-morgan's laws which are : (a+b)' = a' b' ; (ab)' = a' + b'(A'CD + E'F + BCD)'= (A'CD + E'F)' * (BCD)'= (A'CD)' * (E'F)' * (BCD)'= ((A')' + C' + D' ) * ( (E')' + F' ) * (B' + C' + D')= (A + C' + D' ) * ( E + F') * (B' + C' + D')which is the product of sums, that is POS form!
180 vum
I think about $5,000
These words can be made from the word mops: poms mop pom mos oms ops pos som sop mo om op po os so
Find all essential prime implicantsCover the remaining 1's/0's with as few as possible prime implicantsSOP = EPIs + (as few as possible)PIsPOS = (EPIs)(as few as possible PIs)
Sop Moei's population is 7,015.
Sop Poeng's population is 7,977.
The population of Sop Tui is 15,100.
The population of Sop Pat is 5,905.
Sop Tia's population is 12,739.
Sop Khong's population is 6,285.