Illegal use of a median strip refers to activities that violate traffic laws regarding the designated area separating opposing lanes of traffic on a roadway. This can include behaviors such as pedestrians crossing at non-designated points, vehicles making illegal U-turns, or stopping in the median for purposes not permitted by law. Such actions can create hazards for both motorists and pedestrians, leading to potential accidents and traffic violations.
when is it appropriate to use arithmetic mean as opposed to median
you use it when a list of numbers acure
I use it in class when looking at my student's scores... Often I look at mean, median, and mode to decide to reteach a concept or not.
MEAN
in maths
The question is how do the mean and median affect the distribution shape. In a normal curve, the mean and median are both in the same point. ( as is the mode) If a distribution is skewed, its tail is either on the right or the left. If a distribution is skewed the median may be a better value to use than the mean since it has less effect on the shape. Also is there are large outliers, the median has less effect and is better to use. So the mean has a bigger effect on the shape many times than the median.
You would use the median if the data were very skewed, with extreme values.
You could use mode over median or mean when calculating probability. Mode calculates the greatest number of times an object or number will appear.
Perhaps I have some difficulty understanding your question. The mean, median and mode are measures of the center of data or measures of centrality.
mean is the average of numbers in the data set mode is the most frequently occurring value in a data set and median is the middle number of the data set so you would use mean
Illegal drugs mean drugs which is not accepted or it's against the law to use them
Mean is the average you add all the numbers and divide the total by the number of numbers that you added. you would use it rather thank median and mode basically when it asks you to find the mean or to find the average