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A skydiver slows down from 54 ms to 5 ms by opening his parachute. If this takes .75 seconds what is the magnitude of the skydiver's acceleration?
The change in velocity is 54 m/s - 5 m/s = 49 m/s. The time is 0.75 seconds. Using the equation a = (vf - vi) / t, the acceleration is (49 m/s) / (0.75 s) = 65.33 m/s^2.
A skydiver slows down in 54 ms to 4 ms by opening his parachute if it takes 0.75 What is is the magnitude of the skydivers acceleration?
To find the acceleration, we first calculate the change in velocity: 4 m/s - 54 m/s = -50 m/s. Next, we use the formula for acceleration: acceleration = change in velocity / time = -50 m/s / 0.75 s = -66.67 m/s^2. The magnitude of the acceleration is 66.67 m/s^2.
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A skydiver slows down from 54 ms to 4 ms by opening his parachute. If this takes 0.75 seconds what is the magnitude of the skydiver's acceleration?
66.7 m/s2
A skydiver slows down from 54 ms to 4 ms by opening his parachute. if it takes 0.75 seconds what is the magnitude of the skydiver's acceleration?
(4 m/s - 54 m/s)/0.75 s = -50/0.75 m/s² = -200/3 ≈ - 66.67 m/s² (negative because he is decelerating)
A skydiver slows down from 54 m s to 4 m s by opening his parachute this takes 0.75 seconds what is the skydivers acceleration?
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
A skydiver slows down from 65 m s to 5 m s by opening the parachute If this takes 0.75 seconds what is the skydiver's acceleration?
The general formula for acceleration is [(final velocity) - (initial velocity)]/(time required for the change). In this instance, (5 - 65)/0.75 = -80 meters per second per second.
A dog is running at 6.45 m/s. His human calls to him and 3.19 seconds later he is running at 6.56 m/s. What is his acceleration during this time?
0.034 m/s/s
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