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What are some examples of loops in C plus plus?
The following example demonstrates all 4 loop structures in C++. #include<iostream> int main() { int i; std::cout<<"For loop...\n"<<std::endl; for(i=0; i<10; ++i) std::cout<<i; std::cout<<'\n'<<std::endl; std::cout<<"While loop...\n"<<std::endl; i=0; while(i<10) std::cout<<i++; std::cout<<'\n'<<std::endl; std::cout<<"Do-while loop...\n"<<std::endl; i=0; do { std::cout<<i; }while( ++i<10 ); std::cout<<'\n'<<std::endl; std::cout<<"Goto loop...\n"<<std::endl; i=0; again: std::cout<<i; if(++i<10) goto again; std::cout<<'\n'<<std::endl; } Output: For loop... 0123456789 While loop... 0123456789 Do-while loop... 0123456789 Goto loop... 0123456789
What Happens When You kiss a girl on birth control pills?
well in collage about 10 years ago when i was studying to be a doctor i learned that yo can get a std if you kiss a girl that is on birth controls. They said that there is a 2% chance you can get the std aid/HIV but that is not the only std u can get . you can get a lot of std form kissing a girl that is on birth control if you kiss a girl while she is on birth control there is a 67.82% that you will end up with herpes or cancer because all the acid from the pills go in your mouth so be careful. So you have to wait until the girl is off of birth control the u have to wait until 2 months to kiss her so all the acid comes out her body form the pills.Thank you. Doctor Skillman-scrip 2
Can having a messy kisser kiss you result in getting a spot just below your bottom lip in any circumstance?
If they had a cold sore while kissing you, or they have an STD. I'd get myself checked out if I were you.
How do you print 1 to 100 in c without using loop condition?
If you mean you cannot use a for loop, then use a while loop: int i=0 while( i++ < 100 ) std::cout << i << " "; std::cout << std::endl; Or a do-while loop: int i=0; do std::cout << ++i << " "; while( i<100 ); std::cout << std::endl; If these are not allowed either, use a procedural loop: int i=0; again: std::cout << ++i << " "; if( i<100 ) goto again; std::cout << std::endl; If even that is not allowed, then the only option is to hard-wire: std::cout << 1 << " " << 2 << " " << [etc] << 99 << " " << 100 << std::endl; It does seem a pointless exercise when a for loop exists specifically for counting iterations like this: for( int i=1; i<=100; ++i ) std::cout << i << " "; std::cout << std::endl;
Could you kiss your boyfriend on your period?
Yes I Think Because If You Get Your Period Its Not Their Business So Kiss Them __________________________________ Of course you can! Its not as if he's gonna get an STD or anything!
C plus plus program for searching a word from text file?
#include<iostream> #include<fstream> #include<vector> #include<string> std::string get_input_file() { while (true) { std::cout << "Enter the input file name: "; std::string filename; std::getline (std::cin, filename); std::ifstream file (filename); if (file.is_open()) { file.close(); return filename; } std::cerr << "The file could not be opened.\n" << std::endl; } } std::string get_search_word() { while (true) { std::cout << "Enter the word to search for: "; std::string search; std::cin >> search; if (search.size()) return search; std::cerr << "The search word cannot be an empty string.\n" << std::endl; } } std::vector<size_t> get_offsets(const std::string& filename, const std::string& search) { std::vector<size_t> offsets; std::ifstream file (filename); if (!file.is_open()) throw std::exception("The file could not be opened."); size_t offset = 0; while (!file.eof()) { size_t pos = 0; char c; while (!file.read(&c, 1).eof() && c!=search[pos]) ++offset; while (pos!=search.size()-1 && !file.read(&c, 1).eof() && c==search[++pos]); if (pos==search.size()-1 && c==search[pos]) offsets.push_back (offset); offset += pos; pos = 0; } file.close(); return offsets; } int main() { std::cout << "Word Search\n" << std::endl; std::string filename = get_input_file(); std::string search = get_search_word(); std::vector<size_t> offsets = get_offsets (filename, search); std::cout << "The word was found " << offsets.size() << " time" << (offsets.size()==1?"":"s") << ".\n" << std::endl; if (offsets.size()) { std::cout << "Offsets:\n"; for (auto off : offsets) std::cout << off << std::endl; } }
How many blocks on a pallet?
6x8x16 has 120 mixed std and bb while 8x8x16 has 90 all std or bb and 12x8x16 has 60 all std or bb and 16x8x16 has 45 all std or bb. Hope that helps
How many cement blocks on a pallet?
6x8x16 has 120 mixed std and bb while 8x8x16 has 90 all std or bb and 12x8x16 has 60 all std or bb and 16x8x16 has 45 all std or bb. Hope that helps
Turbo C plus plus program to generate addition table from 1 to 10?
#include<iostream> int main() { int x=0; while( x++<10 ) { int y=0; while( y++<10 ) { std::cout<<std::setw(3)<<x+y; } std::cout<<std::endl; } }
How do you write a C plus plus program to delete the repeated words in a sentence?
#include<iostream> #include<string> #include<sstream> #include<vector> #include<stack> std::string convert (const std::string& str) { std::string valid("abcdefghijklmnopqrstuvwxyz"); std::string result; for (auto it=str.begin(); it!=str.end(); ++it) { // convert to lower case const char c = (char) tolower(*it); // ensure character is a letter if (valid.find(c)!=valid.npos) result += c; } return result; } bool equal (const std::string& a, const std::string& b) { return convert(a)==convert(b); } std::vector<std::string> get_words (const std::string& s) { std::vector<std::string> elems; std::stringstream ss (s); std::string item; while (std::getline(ss, item, ' ')) elems.push_back (item); return elems; } std::string remove_duplicates (const std::string& s) { std::vector<std::string> elems = get_words (s); std::stack<std::string> stack; while (!elems.empty()) { std::string last = elems.back(); elems.pop_back(); bool found = false; for (auto it=elems.begin(); !found && it!=elems.end(); ++it) found = equal(last, *it); if (!found) stack.push (last); } std::string result; while (!stack.empty()) { if (result.size()) result += ' '; result += stack.top(); stack.pop(); } return result; } int main() { std::string test_string ("The fox and and the hound."); std::string result = remove_duplicates (test_string); std::cout << "Test string:\t"" << test_string << ""\n"; std::cout << "Result:\t\t"" << result << ""\n" << std::endl; }
How do you split a string in delimit c plus plus?
#include<iostream> #include<vector> #include<string> std::vector<std::string> parse (const std::string& s, const char delim) { std::vector<std::string> result {}; auto start = 0U; auto end = s.find (delim); while (end != s.npos) { result.push_back (s.substr(start, end - start)); start = ++end; end = s.find (delim, start); } result.push_back (s.substr (start, s.npos - start)); return result; } std::vector<std::string> parse (const std::string& s, const std::string& delim) { std::vector<std::string> result {}; auto start = 0U; auto end = s.find (delim); while (end != s.npos) { result.push_back (s.substr(start, end - start)); start = end + delim.length(); end = s.find (delim, start); } result.push_back (s.substr (start, s.npos - start)); return result; } int main() { std::string str1 = "This is a string that will be parsed by a single-space delimiter."; std::string str2 = "This==is==a==string==that==will==be==parsed==by==equal==operator."; std::string str3 = "This string has no delimiter."; std::cout << str1 << std::endl; std::vector<std::string> v1 = parse (str1, ' '); for (auto i : v1 ) std::cout << i << std::endl; std::cout << std::endl; std::cout << str2 << std::endl; std::vector<std::string> v2 = parse (str2, "=="); for (auto i : v2 ) std::cout << i << std::endl; std::cout << std::endl; std::cout << str3 << std::endl; std::vector<std::string> v3 = parse (str3, '\\'); for (auto i : v3 ) std::cout << i << std::endl; std::cout << std::endl; }
Write a program to compute the summation of array elements using pointers?
#include<iostream> #include<random> int main() { std::default_random_engine generator; std::uniform_int_distribution<int> distribution (1,9); std::cout << "Array : "; int a[10]; int* p = a; do { std:: cout << (*p = distribution (generator)) << '+'; } while (++p != a + 10); int sum = 0; p = a; while (p != a + 10) sum += *p++; std::cout << "\b=" << sum << std::endl; }
