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Is cystic fibrosis complete dominance?
Cystic fibrosis (CF) is an autosomal recessive disorder, meaning that the disease manifests only when an individual has two copies of the mutated CFTR gene, one from each parent. In this case, the normal allele is dominant over the mutated allele, which means that carriers with one normal and one mutated allele do not exhibit symptoms of the disease. Therefore, cystic fibrosis is not an example of complete dominance, as the presence of one normal allele can mask the effects of the mutated allele.
What is the genotype of woman with cystic fibrosis?
A woman with cystic fibrosis has a genotype that includes two copies of the mutated CFTR gene, which is located on chromosome 7. This means she is homozygous for the CFTR mutation, typically represented as "ff" where "f" indicates the presence of the cystic fibrosis allele. In cases where she has one normal CFTR allele and one mutated allele, she would be considered a carrier but would not exhibit symptoms of the disease. However, those with cystic fibrosis must have two copies of the mutated gene.
Why can Cystic fibrosis be inherited even if neither parent has the disease?
Cystic Fibrosis is an example of a disease inherited as an autosomal recessive genetic disorder. Both parents of a baby who has Cystic Fibrosis have one abnormal recessive gene and one normal dominant gene and are therefore, Cystic Fibrosis carriers. Carriers are said to be heterozygous because they contain one normal copy of the gene and one abnormal copy. A baby who inherits cystic fibrosis has inherited the abnormal gene from both parents and is therefore said to be homozygous recessive.
Two parents who were phenotypically normal had to children The oldest was also phenotypically normal but the younger child had cystic fibrosis what is happening in the cross?
Cystic fibrosis is an autosomal recessive genetic disorder, meaning that a child must inherit two copies of the mutated gene (one from each parent) to express the condition. In this scenario, both parents are likely carriers of the cystic fibrosis allele (genotype Cc), where "C" is the normal allele and "c" is the mutated allele. The older child is phenotypically normal, which could mean they are either homozygous dominant (CC) or a carrier (Cc), while the younger child inherited two copies of the mutated allele (cc) from both parents, resulting in cystic fibrosis. This cross illustrates Mendelian inheritance patterns, where two carrier parents can have a child with a recessive condition.
Why are individuals who are heterozygous for the cystic fibrosis allele inaffected by the disease?
Individuals who are heterozygous for the cystic fibrosis allele carry one normal copy of the CFTR gene and one mutated copy. Cystic fibrosis is an autosomal recessive disorder, meaning that two copies of the mutated gene are required for the disease to manifest. The presence of one normal gene allows for sufficient production of the CFTR protein, which helps regulate salt and water transport in cells, preventing the development of the disease in heterozygous individuals.
When C equals normal allele and c equals allele for cystic fibrosis Set up and complete a Punnett Square for cystic fibrosis for a couple that both have heterozygous for cystic fibrosis with no sympt?
Sure! When both parents are heterozygous carriers (Cc) for cystic fibrosis, the Punnett Square would result in a 25% chance of having a child with cystic fibrosis (cc), a 50% chance of having a child who is a carrier (Cc), and a 25% chance of having a child who is not a carrier and does not have the disease (CC).
What is the genotype of two normal parents who have a child with cystic fibrosis?
The genotype would have to be homozygous recessive if the child was completely effected by the disease. The "normal" paretns would have to have heterozygous recessive genotypes. This makes sense since the allele that causes sickle cell shows incomplete dominance when present with a normal allele in a pair. The "normal" parents actually would have a mixture of sickle cell shaped red blood cells combined with normal shaped ones. The carrier parents does not display symptoms of the disease since the regular red blood cells alone can fill the body's need for oxygen under normal circumstances. The only time the cArrier would notice would be under times of extreme oxygen demand, such as a sprint.
What are the possible phenotypes of the offspring between a parent who is a heterozygous carrier for cystic fibrosis and a homozygous normal parent?
The chances are one half. You will most likley have 2 children without the gene, and 2 with one gene. Since the normal parent has the dominate allele, the Cystic Fiborisis will not be present.
What is an example of allele frequency?
An example of allele frequency is when in a population of 100 individuals, 60 individuals have the dominant allele (A) for a specific gene, while 40 individuals have the recessive allele (a). The frequency of the dominant allele (A) would be 0.6, and the frequency of the recessive allele (a) would be 0.4.
What are the chances of a normal person and a carrier for cystic fibrosis have a kid with cystic fibrosis?
Zero. Cystic fibrosis is an autosomal recessive disease. This means that both parents must carry a mutated gene and have a 1 in 4 (25%) chance of having a child with CF.
A couple who are both carriers of the gene for cystic fibrosis have two children who have cystic fibrosis What is the probability that their next child will be phenotypically normal?
If both parents are carriers on cystic fibrosis, just because two children may have the disease it doesn't mean that say,a further 3 children in future will be "normal". Inheriting genes is like a lottery. I can say though that because cystic fibrosis is recessive, every offspring born under carriers will always have a 75% chance of being phenotypically normal.
Do carriers have to have cystic fibrosis?
Carriers of cystic fibrosis do not have the disease themselves, as they possess one normal copy and one mutated copy of the CFTR gene. However, they can pass the mutated gene to their children. For a child to develop cystic fibrosis, they must inherit two copies of the mutated gene, one from each parent. Therefore, while carriers do not have cystic fibrosis, they play a crucial role in its inheritance.
