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one MeV has 1,000,000 eVs So one eV has 0.000001 MeVs
1 MeV is equal to 1.6 x 10^-13 volts. Therefore, 5 MeV is equal to 8 x 10^-13 volts.
To convert from mega electronvolts (MeV) to joules, you can use the conversion factor 1 MeV = 1.602 x 10^-13 joules. So, to convert 474 MeV to joules: 474 MeV * 1.602 x 10^-13 joules = 7.595 x 10^-11 joules.
The half value layer (HVL) for a 2 MeV gamma ray in lead is approximately 0.6 cm. This means that a 0.6 cm thickness of lead would reduce the intensity of the gamma rays by half. Lead is commonly used for radiation shielding due to its high density and effective shielding properties against gamma radiation.
To convert joules to megaelectronvolts (MeV), you can use the conversion factor 1 MeV = 1.60218 x 10^-13 joules. Simply divide the energy in joules by this conversion factor to get the equivalent energy in MeV.
None. Hydrogen and Helium are base elements.Helium is helium.Chemically yes, but with Nuclear Physics in stars:H + H --> D + e+ + v + 0.42 MeV, H + H --> D + e+ + v + 0.42 MeV, D + D --> He3 + n + 3.27 MeV (50%)H + H --> D + e+ + v + 0.42 MeV, H + H --> D + e+ + v + 0.42 MeV, D + D --> He3 + H + 4.03 MeV (50%)H + H --> D + e+ + v + 0.42 MeV, H + D --> He3 + gamma photon + 5.49 MeV, H + H --> D + e+ + v + 0.42 MeV, H + D --> He3 + gamma photon + 5.49 MeV, He3 + He3 --> He + H + H + 12.86 MeV (100%)H + D --> He3 + gamma photon + 5.49 MeV (100%)D + D --> He3 + n + 3.27 MeV (50%)D + D --> He3 + H + 4.03 MeV (50%)D + T --> He + n + 17.59 MeV (100%)T + T --> He + n + n + 11.33 MeV (100%)Four or two, depending on the kind of hydrogen isotope you are burning. As you can see in the equations above burning four ordinary atoms of hydrogen to ordinary helium is a complicated and slow process compared to burning two atoms of various isotopes of hydrogen, however a star has such tiny quantities of deuterium and tritium that depending on them for fusion helps little.
None at all.
The conversion factor from kelvin to mega-electronvolts (MeV) is approximately 8.617 x 10-5 MeV per kelvin.
According to 2010 Step-By-Step Medical Coding - Carol J. Buck -Radiation treatment is delivered in units called megaelectron volts (MeV).A megaelectron volt is a unit of energy. The radiation energy delivered by the machine is measured in megaelectron volts; the energy that is deposited in the patient's tissue is measured in Gray (one Gray = 100 rads; 1 centigray [cGy] = 1 rad). A rad is a radiation-absorbed dose.Where as dosimetry is the calculation of the radiation dose and placement. It is common to have several dosimetry or device changes during a treatment course.
First, one finds the beta factor associated with e = 700 MeV. We have 700 MeV/0.511 MeV = gamma = 1369.86 = 1/(1-b^2)^1/2 => b = 0.9999994671. Next, since cos (theta) = 1/(nb) = 0.999710, theta = 1.38 degree.
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