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What is the probability that the children will be heterozygous?
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
If children with blood group O and a what could be the blood group of parents?
both parents could be A heterozygous or one A heterozygous and the other O
What was the probability that two heterozygous parents would have an offspring that produced rounds seeds?
3:4 or 75%
What is probability that two heterozygous parents would have an offspring that produced round seeds?
It is a 75% chance that the seeds will be round.
Will parents with a positive blood type have children with a positive blood type?
There is 50% that children will be of negative blood type if parents are heterozygous positive. 25% if one parent is homozygous and other heterozygous. 0% if both homozygous.
In humans the allele for brown eyes (B) is dominant to the allele for blue eyes (b). What is the probability that two heterozygous brown-eyed parents will have a child with blue eyes?
If both parents are heterozygous for brown eyes (Bb), the possible allele combinations for their children can be represented in a Punnett square: BB, Bb, Bb, and bb. This means there is a 1 in 4 chance, or a 25% probability, that their child will inherit the blue eye genotype (bb) and therefore have blue eyes.
If both heterozygous parents are carriers of a recessive allele for phenylketonuria the probability that a given child of these parents will have PKU is?
The probability that a given child will have PKU is 25%. This is because both parents are carriers of the recessive allele (heterozygous), so there is a 25% chance that they will each pass on the recessive allele, resulting in the child having PKU.
Is it possible for one pair of parents to have some Rh positive children and some Rh negative children?
Yes, this can happen, if the alleles are Hetero for both parents (Rh+Rh-) heterozygous.
If purple flower color is dominant over white flower color how can two purple flowered parents produce while flowered offspring?
It can happen when both parents are a heterozygous
What is probability that wto heterozygous parents would have an offspring that produced round seeds?
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
What is the probability that the offspring will be i barred females?
To determine the probability of offspring being i barred females, we need information about the genetic makeup of the parents, specifically their genotypes related to the i barred trait. If both parents carry the i barred allele, we can use a Punnett square to analyze the potential combinations. The resulting probability will depend on the specific alleles present in the parents. Generally, if both parents are heterozygous for the i barred trait, the probability of producing i barred females could be calculated based on the ratios established in the Punnett square.
What is the probability that two heterozygous parents would have an offspring that produced round seeds?
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
