When HPO42- acts as an acid, it donates a proton to form H2PO4-. H2PO4- is the conjugate base of HPO42-.
In H2O the conjugate base is H2PO4-, being conjugated to the acid H3PO4. As well: H3PO4 is conjugated acid to the base H2PO4-.
The conjugate base of H3PO4 is H2PO4-. The formula for the conjugate base can be found by removing one proton (H+) from the acid molecule.
The dihydrogen phosphate ion - (H2PO4)-is an anion.
H3PO4==============Phosphoric acid.
h2po3
There are two (or actually even three) possibillities: (answer layout: acid + base --> )H3O+ + HPO4- + Na+ --> H2PO4- + Na+ + H2OH3PO4 + OH- + Na+ --> H2PO4- + Na+ + H2O or even the third:2H3O+ + PO43- + Na+ --> H2PO4- + Na+ + 2H2O
H3PO4 (aq) + H2O (l) ---> 2H3O+ (aq) + PO4-3 (aq)donor acid + acceptor base ---> conjugate acid + conjugate basethe answer above is wrongto form a conjugate, the ion H2PO4 - must lose a hydrogen ion H+i.eH2PO4 - -H+ = HPO4 2-(conjugate base)
'Conjugate' means ONE proton more (acid) or less (base) than the described acid or base respectively:So the conjugate acid of PO43- (phosphate) is HPO42- (monohydrogen phosphate)
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
The conjugate acid of H2PO4- is H3PO4. When H2PO4- donates a proton, it forms the conjugate acid H3PO4.
There are three protolysis steps:H3PO4 ---> H+ + H2PO4-H2PO4- ---> H+ + HPO42-HPO42- ---> H+ + PO43-