75
It is: 63%
The mean (average) of 76, 63, 79, 63, and 74 is 71.
Mean of 7 and 63= (7+63)/2 = 70/2 = 35
45 + 63 - 52 = 56.
Assuming you mean 4/9 of 63, you need to multiply 63 by the numerator (in this case, 4), then divide the result by the denominator (in this case, 9). Actually you can also divide first, and then multiply.
for 2 digits... multiply the last digit by 5, add the result to the first digit... example... 63.. (3)(5)=15 15+6=21 21 is divisible by 7, so 63 is divisible by 7...
how do I find the result of 63%
72 To solve, set up 63/x=.875 and solve for x.
Step 1: Find the mean Step 2: Find the deviation from the mean Step 3: Take the absolute value of the deviation Step 4: Find the mean of the absolute deviation. x----x-mean 63 63-63 0 69 69-63 6 62 62-63 -1 57 57-63 -6 64 64-63 1 mean = (63+69+62+57+64)/5 = 63 Taking the absolute deviations, we have 0,6,1,6,1 Averaging these deviations : (0+6+1+6+1)/5 =14/5 = 2.8 Mean absolute deviation = 2.8
63 + 10 = 73. It means 10 + 63 = x
The whole number of 63 is 9 because when you divide 63 by 7, the result is 9. This means that 63 can be expressed as 7 multiplied by 9 (7 x 9 = 63). Thus, 9 is a factor of 63, making it a whole number that evenly divides into 63.