Vestibule
No.
I am bound to take science in school (there's no way out of it).
a portion of space that is bounded on all sides
That depends! The identity operator must map something from a space X to a space Y. This mapping might be continuous - which is the case if the identify operator is bounded - or discontinuous - if the identity operator is unbounded.
interpleural space
It is called a polyhedron.
Yes, unless specifically described as bounded.
Any closed bounded subset of a metric space is compact.
The anterior structures of the vestibular-perineal region include the clitoris, urethra, and vaginal opening. Moving posteriorly, you will find the hymen, perineal body, and anus. The perineum extends between the thighs and is crucial for supporting the pelvic floor muscles.
Almost everything is different!A polygon is a closed shape in 2 dimensional space, bounded by straight lines. Three dimension is a description of normal space.
No. You can always "cheat" to prove this by simply giving the function's domain a bound.Ex: f: [0,1] --> RI simply defined the function to have a bounded domain from 0 to 1 mapping to the codomain of the set of real numbers. The function itself can be almost anything, periodic or not.Another way to "cheat" is to simply recognize that all functions having a domain of R are bounded functions, by definition, in the complex plane, C.(Technically, you would say a non-compact Hermitian symmetric space has a bounded domain in a complex vector space.) Obviously, those functions include non-periodic functions as well.
The web address of the Discovery Space Of Central Pennsylvania is: http://mydiscoveryspace.org