Say your heterozygous condition is Aa. The every gamete has a 50% chance of getting either A, or a. So double the number of gamete types produced, though not double the number of zygote types as 'a' is recessive. Probabilities could change if more that two alleles of a gene exists.
Since problem #1 isn't included in this question we can't give any meaninful answer.
In a system with four different alleles, 4 different types of gametes would be possible. Each gamete would carry one of the four alleles.
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You got the answer yet? Hello anyone got the answer
That depends entirely on the genotypes of the parents.
That depends entirely on the genotypes of the parents.
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Although there are actually several genes which determine ABO-type, they are usually placed into the three basic groups i.e. A, B and O.For each phenotype, the genotypes follow:O: OO is the only possibility.A: AA or AO are both acceptable.B: BB or BO are both acceptable.AB: AB is the only possibility.
The two types of mutations in gamete cells are germ-line mutations, which occur in the sperm or egg cells and can be passed down to offspring, and somatic mutations, which take place in other body cells and are not passed on to offspring.
It is not common to refer to blood types as "genotypes," as blood genotypes are typically represented by combinations of letters and symbols (such as A, B, O, +, -). "Ac" is not a recognized blood genotype in the ABO blood group system.
To accurately answer the question regarding the types of gametes produced by each parent in "problem number 1" and "problem number 2," the specific details of these problems are necessary. Generally, the number of gamete types can be determined by the formula 2^n, where n is the number of heterozygous gene pairs. If you provide more information about the genetic makeup or traits involved in those problems, I can give a precise answer.