A carrier for Niemann-Pick disease typically has a heterozygous genotype, meaning they possess one normal allele and one mutated allele for the NPC1 or NPC2 gene, depending on the specific type of Niemann-Pick disease. This genotype can be represented as "N/n," where "N" denotes the normal allele and "n" the mutated allele. Carriers usually do not exhibit symptoms of the disease but can pass the mutated allele to their offspring.
Rr heterozygous
You can be a carrier of a recessive gene as part of your genotype.
She is a carrier of hemophilia but does not have the condition
If an AC genotype man and an AS genotype woman marry, each of their children has a 25% chance of being born with a sickle cell disease (SS genotype), a 50% chance of being a carrier like their parents (AS genotype), and a 25% chance of having a normal genotype (AA).
If sickle cell anemia is inherited in an autosomal recessive manner, a person with two parents who both have the disease will inherit two copies of the defective gene. Consequently, this individual cannot be a carrier; they will be affected by the disease. In this case, the likelihood of being a carrier is 0%, as they will have the genotype that expresses the disease rather than one that carries it without symptoms.
I think no. It's caused by a recessive gene so if a person has albinism their genotype can only be recessive, recessive ---> AA (small a small a or whatever you call it). No other genotype will mean that person has Albinism, like if it has at least one big A, that means it's just a carrier of albinism.
As long as a persons genotype consists of at least one recessive gene, they can pass it on to offspring to give them the disease, which makes them a carrier. Since this persons genes are both recessive, it is definite that they will pass on the recessive gene.
A genetic carrier has a dominant and a recessive version of an allele. Normally, the term genetic carrier is used in relation to genetic illnesses where two copies of the recessive allele cause that illness. Therefore, a carrier does not have the illness themself (as the dominant, non-disease allele is expressed over the recessive allele). However, they have the ability to create an offspring who has the double recessive genotype and therefore has the condition if they mate with another carrier or someone who is double recessive (who has the disease).
There is not really enough information in the question to answer it properly. You would need to know what trait the D and d stood for to give a proper answer.If the dog's genotype is Dd and it has the disease, this suggests that the disease is caused by a dominant allele. A healthy bitch would have the genotype dd and half of her pups would have the disease. There is no mate which would produce all heathly pups.If the dog is symptom free then the disease is caused by a recessive allele. In which case the dog should be matted with a dog with the genotype DD to have 100% symptom free pups. Mating Dd to Dd would give 75% symptom free pups and 25% sufferers. Mating the Dd dog to a dd dog would give 50% disease free pups and 50% sufferers.
If their genotype contains both a dominant and a recessive allele for a trait.
The host doesnt show symptoms and the carrier does
A carrier for a recessive genetic trait is typically described with a heterozygous genotype, represented as "Aa." In this case, "A" denotes the dominant allele, while "a" represents the recessive allele. The carrier possesses one copy of the recessive allele but does not express the trait associated with it, as the dominant allele masks its effects.