The normal arterial partial pressure of oxygen (PaO2) is typically between 75-100 mmHg when measured at sea level in a healthy individual. Normal arterial partial pressure of carbon dioxide (PaCO2) is usually between 35-45 mmHg.
The alveolar air equation is: PAO2 = FiO2(Pb-47)-(PaCO2/R) where: PAO2 is the partial pressure of oxygen in alveoar gas; FiO2 is the fraction of inspired oxygen (on room air this would be 21%); Pb is the barometric pressure (at sea level this is 760 torr); 47 is the partial pressure of water vapor; PaCO2 is the partial pressure of carbon dioxide in blood; R is the V/Q mismatch, which is 0.8 unless stated otherwise So, if a person is breathing room air at sea level, their PaCO2 is in normal range (let's say 40mmHG, since normal is between 35-45mmHg), and their respiratory rate is 12: PAO2= .21(760-47)-(40/0.8); .21(713)-(50)= 149.73-50=99.73 So the PAO2= 99.73mmHg
1 Torr = 0.00133322 bar 1 Torr = 133.322 Pa 1 Torr = 0.00131578584 ATM 1 Torr = 1 mmHg
1075 torr - 720 torr = 355 torr
1 torr is 0.00131578947 atm. Therefore, 742 torr is 0.976315789 atm.
To convert 760 torr to pascals, you can use the fact that 1 torr is equal to 133.322 pascals. Therefore, you multiply 760 torr by 133.322 pascals/torr: 760 torr × 133.322 pascals/torr = 101325 pascals. Thus, 760 torr is equivalent to 101325 pascals.
To convert psi to Torr, you can use the conversion factor: 1 psi is approximately equal to 51.715 Torr. Therefore, to convert 102.872 psi to Torr, you would multiply by this conversion factor to get approximately 5332.73 Torr.
11,012 torr
1 torr = 0.13 kilopascals. So, multiply torr by 0.13 to get kilopascals.
600 Torr (1 atm/760 Torr) = 0.789 atmospheres ================
each 1mbar = 0.750061673821 torr
Dona Torr was born in 1883.