If you are speaking of the rare type of rickets that is X-linked and when the mother has the gene, the chances are 1:1 or 50:50.
See the link below for more information:
It is approx 0.48
50%
51%..
The probability of selecting 1 female at random is 4/8 There are now 7 students, 3 of which are female so the probability of selecting another female is 3/7 The probability two randomly selected students are female is (4/8)x(3/7)= 3/14
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
1/2.
It is approx 0.4831
its in heat
50% because the male and female would both have the chance
50%, or half. Therefore, there is an equal chance that the offspring will be female.
I work with an infant school including a nursery and so the probability is 1.
The global gender probability, at birth, is approx 0.517 for male and 0.483 for female. This is not the same as the gender ratio at conception because of gender-specific abortion.