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What would be the color vision of children if their mom is colorblind and their dad is normal?
Colorblindness is a recessive, sex-linked trait, and the gene that causes it occurs on the X chromosome. For the mother to be colorblind, she must have two copies of the gene and be homozygous recessive. The father, on the other hand, can not have the gene, because he (as a male) only has one X chromosome. So, if we let Xc represent the recessive gene for colorblindness and Xn represent the normal gene, the the mother is XcXc and the father is XnY. All of their children will receive the recessive gene from their mother. In the males, this means that they will be colorblind, because the chromosome they get from their father will by the Y chromosome. The daughters, however, will get the Xn gene, which is dominant and will override the gene for colorblindness. Thus, all of the couple's sons will be colorblind, and none of their daughters will be.
What if Mary and her mother are both colorblind is Mary's father colorblind too?
If Mary's mother is colorblind, and therefore carries the colorblind gene on one of her X chromosomes, then Mary would inherit that gene as well. If Mary's father is colorblind, he would have to pass on his X chromosome with the colorblind gene to Mary, making her colorblind too. If only Mary's mother is colorblind, Mary's father is likely not colorblind.
How many individuals in Generation II of the family have the gene for nearsightedness?
Two individuals in Generation II carry the gene for nearsightedness.
Why is a son who receives the allele for combinations from his mother always colorblind?
Since the mother would be considered a carrier, the gene will be produced in the offspring. the son will receive that gene and will be colorblind.
If a color blind man has a color blind daughter then the mother has to be color blind as well?
The father has to be colorblind for the daughter to be colorblind because both X chromosomes must have the colorblindness gene in females because the colorblind gene is recessive. If only the mother is color deficient, then she merely passes on the gene to one of the X chromosomes in a female. If both the mother and father are both colorblind, then both X chromosomes in the female are effected and the female is colorblind. There are two scenarios in which a daughter may be born colorblind. 1. The father is colorblind and the mother is a carrier of the colorblind gene. The daughter will be either colorblind or a carrier of the colorblind gene. 2. The father and mother are both colorblind. If this is the case, then all of the children will be born colorblind.
Why are there more men that are colorblind then women?
It has to do with the slight differences in the DNA, ANSWER Colorblindness is sex linked trait. Females are XX and Males are XY. The colorblind gene is only on the X chromosome so if a male has the gene on the X chromosome then he will be colorblind. Females can have it on one X chromosome, but not the other and not be colorblind; however, they are a carrier and can pass it on. For a female to be colorblind both X chromosomes must have the gene.
In humans normal color vision is dominant over colorblindness. A colorblind male marries a female who is a carrier for color blindness. What is the probability that a colorblind child would be born to?
The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.
What are the chances of a male with normal vision and a color-blind female having a color blind son?
Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy) So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
What is the probability that a woman who is a carrier of the colorblind gene and a colorblind man will have a daughter who will be colorblind?
the colorblindness is usually not activited in a female body but is usually seen in male
If a color blind male who has normal clotting blood marries a female who is a carrier of hemophilia and has normal color vision could they have a color blind child?
In short, hemophilia has nothing to do with colorblindness, but YES, they could have a colorblind child if she is a carrier for the colorblindness gene. Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Any of her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
Father isn't colorblind mother is a carrier--one son is colorblind but the other is not how?
It is called x-linked alleles. It is rare for a female to have color blindness because the allele must be passed from both parents. Males only need one allele to be color blind.With the equation, color blind female and non-color blind male reproduce. Each son has a 50% chance of developing the disorder.
When does colorblindness occur?
it usually happens if one of your parents have the gene of color blindness or it somewhere in the family. and it just depends how bad it is.
