No. 80mg equals .08 grams
To determine how many grams of morphine are in 0.05 mL of liquid morphine, you need to know the concentration of the liquid morphine, which is typically expressed in mg/mL. For example, if the concentration is 10 mg/mL, then 0.05 mL would contain 0.05 mL × 10 mg/mL = 0.5 mg of morphine. Since there are 1000 mg in a gram, 0.5 mg is equal to 0.0005 grams of morphine. The specific conversion depends on the concentration of the liquid morphine used.
The concentration of morphine can vary, so it's important to know the specific concentration of the morphine solution. However, for a standard concentration of 1 mg/mL, 2 mg of morphine would be equal to 2 mL.
30 mg of Morphine IR is equal to approximately 8 mg of Diluadid, so there is about a 4mg morphine to 1 mg of dilaudid ratio. So 45 mg of morphine would be equal to 5.6 mg of dilaudid. To answer your question, 45 mg of Morphine IR would stronger than taking the 4 mg of dilaudid.
0.08 grams
1000 mg = 1 g so 80 mg = 0.08 grams
6119mg is equal to 6.119 grams (mg divided by 1,000 = grams)** 1 gram = 1,000mg
255mg is equal to 0.255 grams (mg divided by 1,000 OR mg x 0.001 = grams)** 1 gram = 1000mg
87.6 mg = 0.0876 grams
80 mg = 0.08 g80 mg = 0.08 g80 mg = 0.08 g80 mg = 0.08 g80 mg = 0.08 g80 mg = 0.08 g
There are 1000 mgs to a gram. 80 mg would be 8/100ths of a gram, or 0.08 grams
1 mg = .001 grams, so .014 mg = 0.000014 grams
9000 mg