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How many liters of 10 percent alcohol solution must be mixed with 70 liters of a 70 percent solution to get a 30 percent solution?
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What does it mean if saturation level is 70 percent?
example: say saturation level of sugar in water is 70 percent, if the solution is 70 percent sugar, it is saturated
How many gallons of a 80 percent solution must mix with 70 gallons of 10 percent solution to get 70 percent solution?
420 gallons. Here's how to find it; If X = Gallons of 80% mix, 0.8*X + 0.1*70 = 0.7*(X+70) Which we can then solve, 0.8X + 7 = 0.7X + 49 0.1X = 42 X = 420
If you have an order for 20 percent dextrose 500 ml you have 1000 ml bag of dextrose 70 percent how much of the dextrose 70 percent do you need to use to make dextrose 20 percent 500 ml?
To make a 20% dextrose solution, you need to dilute the 70% dextrose solution with water. You need to use 178.57 ml of the 70% dextrose and 321.43 ml of water to make 500 ml of 20% dextrose solution.
How much pure acid should be mixed with 5 gallons of 70 percent acid solution in order to get a 90 percent acid solution?
x=45
How many gallons of a 80 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 70 percent antifreeze?
if z is the answer then you are going to end with (70 + z) gallons of solutionto find out what z is you use this formula: .8z + (70 x .3) = .7(z + 70)this yields: .8z - .7z = 49 - 21.1z = 28 or z = 280 gallonsnote that decimals are used for the percent values-- 80% = .8 etc
How much 95 percent alcohol must be used to prepare 1000 ml of 70 percent alcohol?
To prepare 1000 ml of 70% alcohol solution, you would need to mix 700 ml of 95% alcohol with 300 ml of water. Starting with a base of 95% alcohol ensures that the final solution will be at least 70% alcohol.
How many gallons of a 80 percent antifreeze solution must be mixed with 70 gallons of 20 percent antifreeze to get a mixture that is 70 percent antifreeze?
70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze. Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze. Total volume of solution = G + 70 gallons Volume of antifreeze required in this solutions to make it a 70% solution is 0.7*(G + 70) = 0.7G + 49 gallons. Volume of antifreeze = 14 + 0.8G gallons So 0.7G + 49 = 14 + 0.8G 0.7G + 35 = 0.8G 35 = 0.1G 350 = G Answer: 350 gallons.
How many gallons of a 50 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 40 percent antifreeze?
70gallons
If you have a 70 percent solution of dextrose How many grams of dextrose is in 400ml of this solution?
In a 70% dextrose solution, 70% of the total weight is dextrose. To calculate the grams of dextrose in 400ml of this solution, you would multiply 400ml by 70% (or 0.70) to find the amount of dextrose present.
How many gallons of a 70 percent solution must be mixed with 70 gallons of 10 percent antifreeze to get a mixture that is 60 percent antifreeze?
Say x = total gallons of solution at 60%Say y = gallons of 70% solutionx=70+y gallonsThen .60x = .70y + .1(70)substituting for x gives.60(70) + .60y = .70y + .1(70) or42 + .6y = .7y + 7 or42-7 = .1y gives y = 350 gals and x = 420 gals total solutionThe answer is 350 gallons
70 percent of a can of paint has been used What percent of paint is left in the can?
...erm, 30%
