X/i/mxmi
Improved answer:
In today's terms it is: X-I-MCMXCI
Forty = XL And Fifty = L The in between is the same as 1-10
The Roman Numerals were invented by the Romans because they did not have numbers in their days like we do now. So... they made values for the letter of Roman Numerals. Example: M= 1,000 D= 500 C= 100 L= 50 X= 10 V= 5 I= 1
DXXIV would be 526. D=500 X=10 X=10 I=1 V=5
There is no Roman numeral represented by the letter T. The most common numerals used are... I = 1, V = 5, X = 10, L = 50, C = 100, D = 500 and M = 1000.
The roman numerals of XVI = 16 because X = 10, V = 5 and I = 1 XVI*XVI = X*XVI + V*XVI + I*XVI = CLX + LXXX + XVI = CCLVI (256)
It is normally only customery to dislpay years in roman numerals. 17 = XVII = 10 + 5 + 1 + 1 3 = III = 1 + 1 + 1 1991 = MCMXCI = 1000 + (1000 - 100) + (100 - 10) + 1 So 17/03/1991 = XVII / III / MCMXCI
The roman numerals for 1-10 are as follows:IIIIIIIVVVIVIIVIIIIXX
January 18th, 1991 in roman numerals would be: I/XVIII/MCMXCI
1991
I-XXX-MCMXCI
Today's way of converting 1-5-1991 into Roman numerals is I-V-MCMXCI. But the Romans themselves in times past would have probably wrote the number 1991 as MDCCCCLXXXXI.
The equivalent prime numbers from 1 to 10 in Roman numerals are: II, III, V and VII
Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.Eleven in Roman numerals is XI.
12 in roman numerals is XII (10+1+1) 1938 in roman numerals is MCMXXXVIII (1000-100+1000+10+10+10+5+1+1+1_
MCMLXXIII = 1000 + (1000 - 100) + 50 + 10 + 10 + 1 + 1 + 1 = 1973.
In today's terms: I-I-MCMXCI
I-XXVII-MCMXCI