First let us find the deceleration ie a = F/M
Plugging F = 500 and M = 1000, we get a = 1/2 = 0.5 m/s2
20 ms has to be 20 m/s. So u = 20 m/s and final v = 0 as it comes to rest finally.
Let us use the equation of motion where time is absent.
So v2 = u2 + 2 a s.
Plugging and rearranging we get s = 20 x 20 / 2 x 0.5 = 400 m.
The distance moved right from the time of applying the force till it comes to rest is 400m
The force varies as the square of the distance
yes you can by using pulleys levers and a wedge. these objects help you move another object without your body moving.
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In general they SHORTEN your stopping distance as they can apply more force to the breaks.
stopping distance is the distance it takes for a vehicle to come to a full stop from the moment you apply the brakes
No, they have different meanings.Following distance is the safe distance to follow behind a moving motor vehicle.Stopping distance is the combination of the drivers reaction time to apply the brakes and the time the vehicle takes to come to a halt.
Yes, reaction time is a component of total stopping distance. It represents the time it takes for a driver to perceive a hazard and apply the brakes to begin stopping the vehicle.
An element of total stopping distance is the reaction distance, which is the distance your vehicle travels from the moment you see a hazard until you physically apply the brakes. This, combined with the braking distance (the distance your vehicle travels once the brakes are applied until it comes to a complete stop), makes up the total stopping distance.
Given a force of -500 N, which implies braking, the stopping distance of the car can be calculated using the equation ( d = v^2 / 2a ), where ( d ) is the stopping distance, ( v ) is the initial velocity (20 m/s), and ( a ) is the acceleration produced by the force. Using Newton's second law, we have ( a = F / m = -500 / 1000 = -0.5 , \text{m/s}^2 ). Substituting ( v = 20 , \text{m/s} ) and ( a = -0.5 , \text{m/s}^2 ) into the stopping distance equation, we get ( d = 20^2 / (2 \times 0.5) = 400 , \text{m} ). Hence, the stopping distance for the car will be 400 meters.
It means the minimum distance the car moves between the time the driver decides to stop and the time the car actually stops. The distance can never be zero, and any pedestrian or animal who happens to be crossing in front of the car at a distance less than the stopping distance is simply out of luck.
The stopping distance is the distance between the driver and the traffic lights which is required to come to a complete stop. There are many factors which are involved in the stopping distance of the car, such as: Weather, Braking systems and Tyre Threading. There are many more, but these are the main ones. If a driver wants to come to a complete stop before driving over the traffic line or causing an accident he/she needs to be on high alert and apply the brakes at a good distance at the right time.
To calculate the stopping distance, you need to first find the acceleration using the formula F = ma, where F is the force, m is the mass, and a is the acceleration. Once you have the acceleration, you can use the formula v^2 = u^2 + 2as, where v is the final velocity (0 m/s in this case), u is the initial velocity, a is the acceleration, and s is the stopping distance. Solve for s to find the stopping distance.
Yes, the critical factor in the distance it takes to stop your vehicle is your reaction time and the braking distance. Reaction time is the time it takes for you to perceive a hazard and apply the brakes, while braking distance is the distance your vehicle travels after applying the brakes until it comes to a complete stop. Both factors contribute to the overall stopping distance of your vehicle.
The kinetic energy of the vehicle when it is travelling faster is four times as great. It the brakes apply the same retardation and the friction from the tires on the road surface is unchanged then the stopping time will be four times as long.
If you apply the brakes it can stop it moving.