C program for leap year using conditional operator?

Answer 1

#include

#include

void main()

{

int y;

clrscr();

print f ("enter a year");

scan f ("%d",&y)

(y%100==0):((y%400==0)?print f("% d is leap year",y):print f("%d is not leap year",y):((y%4==0)? print f ("d is leap year",y): print f ("%d is leap year",y): print f ("%d is not leap year,y));

getch();

}

Answer 2

There are two steps to find out:

Step-1: If the given year is divisible by 4 but not divisible by 100, then the given year is leap year.

But in some certain cases, this formula is not applicable. However, if the above formula is not success, to confirm your answer, go to step 2.

Step-2: Divide the given year by 400 and if it is divisible by 400, you can confirm that the given year is Leap year. If not divisible by 400, it is not Leap year.