#include
#include
void main()
{
int y;
clrscr();
print f ("enter a year");
scan f ("%d",&y)
(y%100==0):((y%400==0)?print f("% d is leap year",y):print f("%d is not leap year",y):((y%4==0)? print f ("d is leap year",y): print f ("%d is leap year",y): print f ("%d is not leap year,y));
getch();
}
leap yr = ((y%100!=0 && yr %400==0)?1:(yr%4==0)?1:0; leap yr =1; printf ("leap yr"); else printf ("not leap yr");
true
You can use a number of nested "if" commands. The rules are the following: If the year is a multiple of 400, it IS a leap year. Else, if the year is a multiple of 100, it's NOT a leap year. Else, if the year is a multiple of 4, it IS a leap year. Else it's NOT a leap year. In Java, to check for divisibility, you use the "%" operator, which gives you the remainder of a division. For example: if (year % 400 = 0) ... To show results on screen, you use: System.out.println(...)
Great Leap Forward
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dono
If the year divides evenly by 4 it's a leap year. If it's a century year it has to divide evenly by 400. 2000 was a leap year. 2100 will not be a leap year.
3900
#include using namespace std;int main(){short numberOfDays = 0;cout > numberOfDays;if (numberOfDays == 365){cout
jete
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