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It is every 7 years, but because of the leap years within the 7 years, it adds an extra 2 years for everytime a leap year occurs within the 7 years. The exceptions are 2000, 2028, 2056, 2084, etc. Everytime an exception occurs, that 7 years become 6, making the pattern look like 11, 11, 6, 11, 11, 6, 11, 11, 6. There are two sets of 11 years then 6 years (exception to the rule) hence the pattern. every 28 year is an exception (6). otherwise, 11, 11. So there are two patterns. The 11, 11, 6 sets and the every 7 years + 4yr to create 11 years.

Simple answer: Every 7 years plus 2 years for every leap year that falls withing the 7 years changing the 7 to 11

I was born on November 25th 1971 (Thanksgiving day) as well. There is a pattern, but Jay has just introduced a level of confusion because 2032 will not usher in thanksgiving on November 25th, so there is no 5 years to the pattern. The pattern is simple, it is 11, 11, 6, 11, 11, 6, 11, 11, 6

11 and 6 years. The 6 compensates for the leap year.

So here goes We were born on Nov 25th (1971) (thanksgiving day). A leap year is a year that is evenly divisible by 4, with a few exceptions.

From 1971, the next time thanksgiving should have fallen would have been 1979, but you have to add 2 years everytime a leap year fell between 71 and 79. There were 2 leap years. (1972 and 1976). So you have to add 4 years to the 7 years, resulting in 11 years pushing (1971 to 1982). Then from 1982 to 1989, how many leap years? Another 2 (84 and 88)-years evenly divisible by 4.

So add 4 years to 7 again and 1982 pushes past 1989 to 1993 (1982 + 7yrs +4yrs)= 11yrs 1982 to 1993.

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12y ago

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