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What is probability of non-leap year has 53 Sundays?
The year MUST start on a Sunday. For a leap year, it can start on Saturday or Sunday. In any period of 400 years there are 303 non-leap years, of which 43 begins and ends with a Sunday, and there are 97 leap years, of which 28 begins with a Saturday or a Sunday. So the probability in a non-leap year is 43/303, or 14.2%. And the probability in a leap year is 28/97, or 28.9%
What is the probability of getting 53 Fridays in a leap year?
A leap year is 52 weeks plus 2 days. That means that 2 days have 53 instances. So there is a 2/7 chance that there will be 53 Fridays. There is absolutely no chance that there are 54 Sundays, since 53 is the most you can have. Good luck. The exact probability is 28/97, which is about 28.87%.
What is probability that a leap years selected at random will contain 53 Sundays?
probability = 2/7 to be exact, 28/97 (about 28.87%)
What is the probability that a leap year selected at random will contain you 53 Sundays II 53 Thursdays?
A Leap year has 366 days. in which you have 52 weeks and 2 days. the 2 days may be sun,Mon mon,Tue tue,wed wed,THu, thu,Fri FRi,SAT sat,sun so you have 7 options among which 2 u can choose.. so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7. The probability of having either 53 Sundays or 53 Thursdays is 4/7.
Probability of times Sunday in leap year?
In a leap year, there are 366 days, which consist of 52 weeks and 2 extra days. Since each week has one Sunday, there are 52 Sundays in the 52 weeks. The 2 extra days can be any combination of days, which means that there is a possibility of having one or two additional Sundays depending on whether those extra days include a Sunday. Therefore, in a leap year, the total number of Sundays can be either 52 or 53.
What is the probability of getting 53 Sunday in a leap year?
Total number of days in a leap year is 366, ie 52 weeks and 2 days. The last 2 days can be either ( Mon Tue, Tue Wed, Wed Thu, Thu Fri, Fri Sat, Sat Sun, Sun Mon) The possible outcomes are 7 The outcomes where one of the day is a Sunday is 2 So probability of getting 53 Sundays is = 2/7. The exact probability is 28/97, which is about 28.87%.
How many Sundays in a leap year?
52 unless 1 or 2 January is a Sunday - in which case, 53.
What is the probability that at least 2 people in the class of 25 will share the same birthday?
Birthdays are not distributed uniformly over a year but if, for the sake of probability games you assume that they are, then ignoring leap years, the probability is 0.5687. Including leap years, it is slightly lower.
What is the probability that a leap year has 52 Mondays?
In a leap year, there are 366 days, which equates to 52 weeks and 2 extra days. These extra days can be any combination of two consecutive days of the week. Since a leap year can start on any day of the week, the combinations that include Monday are: Monday-Tuesday, and Sunday-Monday. Thus, the probability of having 52 Mondays in a leap year is 5 out of 7, or approximately 71.4%.
What is the probablity for 52 weeks in the year?
Zero. Each year is either 52 weeks and 1 day, or 52 weeks and 2 days (Leap Year). So no year is 52 weeks and so probability = 0.
What is the chance that a leap year selected at random will contain 53 Saturdays?
Since you are selecting only among leap years, either the first or the second day of the year would have to be a Saturday, so you have two chances out of seven (a probability of 2/7) that there are 53 saturdays.
How many full days in a leap year?
you divide 366 by 2 and you get 183 days that is half of a leap year
