5d bend
In the context of bend pipes, "6D" refers to the bend radius being six times the nominal diameter of the pipe. For example, if the pipe has a diameter of 2 inches, a 6D bend would have a radius of 12 inches. This specification is important for ensuring smooth flow and reducing turbulence in piping systems. It is commonly used in various engineering applications to maintain structural integrity and optimize fluid dynamics.
2(3d+7)=5+5d. 6d+14=5+5d 6d+9=5d 9=-1d d=-9 I think that's correct. If it is, ur welcome.
5D and similar bends with a large radius are used in pipelines carrying sludge or slurry - such as in wastewater plants,and in pneumatic conveying systems . They reduce resistance to flow / pipeline losses and reduce the risk of blockage.
To simplify the expression 5d + 2(3d), you first distribute the 2 to the terms inside the parentheses, which gives you 5d + 6d. Combining like terms, you add the coefficients of the d-terms together to get 11d. Therefore, the simplified expression is 11d.
Do you mean: 11d +1 = 5d+49? If so: 11d+1 = 5d+49 11d-5d = 49-1 6d = 48 d = 8
5d-4=4-d you have to bring the d to one side and the 4 to the other remember there is a 1 in front of the d so you'll get 6d-4=4 then you get 6d=8 then you divide and get d=4/3 or 1 and 1/3
'3d-, 4d-, 5d-, 6d-block' elements are in groups 3-12 in period 4, 5, 6 and 7 respectively.
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p
'3d-, 4d-, 5d-, 6d-block' elements (groups 3-12) in period 4, 5, 6 and 7 respectively)
If Q=quarter, D=dime, N=nickel, and P=penny, then 3Q 2Q + 2D + 1N 2Q + 2D + 5P 2Q + 1D + 3N 2Q + 1D + 2N + 5P 2Q + 1D + 1N + 10P 2Q + 5N 2Q + 4N + 5P 2Q + 3N + 10P 2Q + 2N + 15P 2Q + 1N + 20P 2Q + 25P 1Q + 5D 1Q + 4D + 2N 1Q + 4D + 1N + 5P 1Q + 4D + 10P 1Q + 3D + 4N 1Q + 3D + 3N + 5P 1Q + 3D + 2N + 10P 1Q + 3D + 1N + 15P 1Q + 3D + 20P 1Q + 2D + 6N 1Q + 2D + 5N + 5P 1Q + 2D + 4N + 10P 1Q + 2D + 3N + 15P 1Q + 2D + 2N + 20P 1Q + 2D + 1N + 25P 1Q + 2D + 30P 7D + 1N 7D + 5P 6D + 3N 6D + 2N + 5P 6D + 1N + 10P 6D + 15P 5D + 5N 5D + 4N + 5P 5D + 3N + 10P 5D + 2N + 15P 5D + 1N + 20P 5D + 25P 4D + 7N 4D + 6N + 5P 4D + 5N + 10P 4D + 4N + 15P 4D + 3N + 20P 4D + 2N + 25P 4D + 1N + 30P 4D + 35P AND SO ON
The order of electron orbitals following the Aufbau principle is: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, and 7p. Electrons fill the orbitals in increasing energy levels.
If -6d = 42 then 6d = -42. then divide by 6, d = -7