The correct answer is:
BH3 sp2
BeCl2 sp
PCl5 sp3d
NH3 sp3
SF6 sp3d 2Type your answer here...
To predict the hybridization of the central atom in a molecule or ion, you can use the formula: hybridization = (number of valence electrons on central atom + number of monovalent atoms attached to the central atom - charge)/2. This will give you the approximate hybridization state of the central atom based on the number of regions of electron density around it.
check valence electron
sp, linear, linear
E. sp D. sp2 B. sp3 C. sp3d A. sp3d2
The central atom of HClO3- is chlorine. The hybridization of the central chlorine atom in HClO3- is sp3.
The central atom in IF4+ is iodine. Iodine has 7 valence electrons and forms 4 sigma bonds in IF4+ resulting in a hybridization of sp3d2 (5 electron domains).
The hybridization of SiBr4 is sp3 because the silicon atom is bonded to four bromine atoms, requiring four electron pairs in the valence shell to form four sigma bonds, thus resulting in sp3 hybridization.
H2=2 And S=6 So2+6=8
The hybridization of the valence electrons on the nitrogen atom in NO+ is sp. The electron pair geometry is linear, and the shape of the ion is also linear.
In a tetrahedral molecule, the central atom has 0 unshared pairs of valence electrons. The central atom forms four chemical bonds with surrounding atoms, resulting in a total of 4 electron pairs around the central atom.
SF6 sp3d2H2S sp3ICl3 sp3dBF3 sp2CS2 sp
The central atom in BCl3 is boron, which has only three valence electrons. Since it forms three bonds with the chlorine atoms, the hybridization of the central boron atom is sp2.