0
What else can I help you with?
What is the shortest vertebrate?
The cervical vertebre are the smallest, the smallest of those is C1.
How do you add colors in c?
Eg: typedef struct RGB { unsigned char R, G, B; } c1, c2, csum; ... if ((int)c1.R + (int)c2.R > 255) csum.R = 255; else csum.R = c1.R + c2.R; if ((int)c1.G + (int)c2.G > 255) csum.G = 255; else csum.G = c1.G + c2.G; if ((int)c1.B + (int)c2.B > 255) csum.B = 255; else csum.B = c1.B + c2.B;
Add the contents of cells C1and C2 together?
type into a given cell =c1+c2 If you mean words, use this =c1&c2 which means join the string values.
Which island is locates in grid squares c1 and c2?
Alexander Island.
2 capacitances are in parallel gives 6 micro farad and in series gives 25 what will be the value of individual capacitance?
Let K1 & K2 be the equivalent capacitence in series and parallel resp. if c1 and c2 b the values of capacitor we have 1/c1+1/c2=1/6 c1+c2=25 solving we get c1=10 MF c2 =15 MF or vice cersa
What pivots on c2 and lacks a body?
A seesaw or teeter-totter is an object that pivots on a central point (c2) and lacks a body in the traditional sense.
Why is an intervertebral disc not present between C1 and C2?
yes. the atlas and axis, or C1 and C2, do not have an intervertebral disc, nor an intervertebral foramen, between them. C1 looks like an oval. it has two lateral masses (no vertebral body) where it makes contact with the occiput and C2. the inferior articular facets of the C1 and the superior articular facets of C2 form 2 joints, one on each side. there is also a third joint formed by the dens, or odontoid process, of C2 and the interior of the anterior arch of C1. this is the joint you use to shake your head "no".
Is it possible for a system of two linear inequalities to have no solution and be parallel?
Yes, it is possible. Since their boundaries are parallel the relevant equations are of the form y = mx + c1 and y = mx + c2. Then if c1 > c2, the inequalities must be of the form y ≥ mc + c1 and y ≤ mx + c2
Write a program to find sum of two complex numbers?
#include<iostream.h> #include<conio.h> class complex { int a,b; public: void read() { cout<<"\n\nEnter the REAL PART : "; cin>>a; cout<<"\n\nEnter the IMAGINARY PART : "; cin>>b; } complex operator +(complex c2) { complex c3; c3.a=a+c2.a; c3.b=b+c2.b; return c3; } complex operator -(complex c2) { complex c3; c3.a=a-c2.a; c3.b=b-c2.b; return c3; } complex operator *(complex c2) { complex c3; c3.a=(a*c2.a)-(b*c2.b); c3.b=(b*c2.a)+(a*c2.b); return c3; } complex operator /(complex c2) { complex c3; c3.a=((a*c2.a)+(b*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); c3.b=((b*c2.a)-(a*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); return c3; } void display() { cout<<a<<"+"<<b<<"i"; } }; void main() { complex c1,c2,c3; int choice,cont; do { clrscr(); cout<<"\t\tCOMPLEX NUMBERS\n\n1.ADDITION\n\n2.SUBTRACTION\n\n3.MULTIPLICATION\n\n4.DIVISION"; cout<<"\n\nEnter your choice : "; cin>>choice; if(choice==1choice==2choice==3choice==4) { cout<<"\n\nEnter the First Complex Number"; c1.read(); cout<<"\n\nEnter the Second Complex Number"; c2.read(); } switch(choice) { case 1 : c3=c1+c2; cout<<"\n\nSUM = "; c3.display(); break; case 2 : c3=c1-c2; cout<<"\n\nResult = "; c3.display(); break; case 3 : c3=c1*c2; cout<<"\n\nPRODUCT = "; c3.display(); break; case 4 : c3=c1/c2; cout<<"\n\nQOUTIENT = "; c3.display(); break; default : cout<<"\n\nUndefined Choice"; } cout<<"\n\nDo You Want to Continue?(1-Y,0-N)"; cin>>cont; }while(cont==1); getch(); }
What is a quadratic curve?
A quadratic curve has the form C2X2+C1X1+C0 where (C2,C1,C0) are coefficients. If C2=0, it degrades to the equation for line. C1 or C0 may also =0
How do you know when an equation has infinite answers?
say system of equation is as follows a1x + b1y = c1 a2x + b2y = c2 if a1/a2 = b1/b2 = c1/c2 equation will have infinite answers
How do you get the proof for Delta Star transformation in capacitors?
Convert all your capacitances to their equivalent impedance, then use Y-Delta Conversion formulae. Impedances mix and match like resistances. If the resistor version is: (Y to delta) Ra = (R1*R2 + R2*R3 + R3*R1)/R2 Rb = (R1*R2 + R2*R3 + R3*R1)/R3 Rc = (R1*R2 + R2*R3 + R3*R1)/R1 Then the capacitor version looks like: Ca = C1*C3/(C1 + C2 + C3) Cb = C1*C2/(C1 + C2 + C3) Cc = C2*C3/(C1 + C2 + C3)
