A Calculater???????????????????????????????????
No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
yes
I can give the width of one of the rectangles. The first rectangle of area 15 cm2 and length of 5 cm has width of 3 cm. It is impossible to know the width of the other rectangle of area 60 cm2. However, if you had said that the two rectangles were similar, then the dimensions of the second rectangle would be 10 cm X 6 cm. But you didn't say that the two rectangles were similar; so there are infinite possibilities of what the dimensions of the second rectangle might be.
A+=14 * * * * * Not sure what the above answer means. But whatever it is, it is not the correct answer to this question! ae is half of ad so the second figure has the linear dimensions of the second are half that of the first. Therefore, the perimeter is half ie 27 units.
No.For example, a 1 metre * 72 metre rectangle and a 8 metre * 9 metre rectangle both have areas of 72 square metres. But the perimeter of the first is 146 metres while that of the second is 34 metres.
the formula for the perimeter of a rectangle is p = 2W + 2L, where L is the length and W is the width, so your first equation is 126 = 2W + 2L"twice as long as it is wide" means that the length L is 2 times the width W, so your second equation is L = 2WIn order to solve for the dimensions, you can substitute L for 2W in the first equation to get:126 = L + 2L126 = 3LL = 126/3L = 42and because L = 2W:42 = 2WW = 42/2W = 21
Yes, your statement is dimensionally correct. But your formula is incorrect, and possibly ambiguous. First, the perimeter is only a simple sum involving length and width IF the figure is a rectangle. Second, the perimeter of the rectangle is double what you have stated: P = 2L + 2W
You can write equations for each of the two facts provided, then solve the equations. If you call the length "l", and the width "w", the facts are:3 more than...: w = 2l+3 perimeter: 2(l+w)=60 This is fairly easy to solve if you replace the first equation in the second (in the second equation, replace "w" by the expression that is on the right, in the first equation).
No. In the first place, the word is "multiply", not "times", and in the second place, to get the width you divide the perimeter by two and then subtract the length (there are alternative methods, but none of them is even close to multiplying the length by the perimeter).
== == The corresponding angle is 60 degrees.
The question cannot be answered. First, there is no information as to which measure of the rectangle is 14 units: a diameter, the perimeter, the area. Second, the answer to the question above does not provide sufficient information to answer the question.